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Elodia [21]
4 years ago
11

How many milliliters of 0.120 m naoh are required to titrate 50.0 ml of 0.0998 m benzoic acid to the equivalence point? the ka o

f benzoic acid is 6.3 ⋅ 10-5?
Chemistry
1 answer:
madam [21]4 years ago
6 0
<span>Answer: moles acid = 0.0500 L x 0.0998 = 0.00499 = moles NaOH V = 0.00499/ 0.120 = 0.0416 L >> 41.6 mL</span>
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