2. What procedure did you use to complete the lab?
Outline the steps of the procedure in full sentences.
Section II: Observations and Conclusions
3. What charts, tables, or drawings would clearly show what you have learned in this lab?
Each chart, table, or drawing should have the following items:
a. An appropriate title
b. Appropriate labels
4. If you could repeat the lab and make it better, what would you do differently and why?
There are always ways that labs can be improved. Now that you are a veteran of this lab and have experience with the procedure, offer some advice to the next scientist about what you suggest and why. Your answer should be at least two to three sentences in length.
Writing the Lab Report
Now you will use your answers from the four questions above to write your lab report. Follow the directions below.
Section I: Overview of Lab
Use your answers from questions 1 and 2 (above) as the basis for the first section of your lab report. This section provides your reader with background information about why you conducted this lab and how it was completed. It should be one to two paragraphs in length.
Section II: Observations and Conclusions
Use your answers from questions 3 and 4 (above) as the basis for the second section of your lab report. This section provides your reader with charts, tables, or drawings from the lab. You also need to incorporate your answers to the follow-up questions (from the Student Guide) in your conclusions.
Answer:
26.4g
Explanation:
The balanced chemical equation as stated in this question is given as follows:
Fe2O3 + 3CO → 2Fe + 3CO2
According to this balanced equation, 3 moles of carbon monoxide (CO) will react with 1 mole of Ferric oxide (Fe2O3).
We need to change 50.26 g of ferric oxide to moles by using the formula;
mole = mass/molar mass
Molar mass of Fe2O3 = 56(2) + 16(3)
= 112 + 48
= 160g/mol
mole = 50.26/160
mole = 0.314mol of Fe2O3
If 3 moles of carbon monoxide (CO) will react with 1 mole of Ferric oxide (Fe2O3).
Hence, 0.314 mol of Fe2O3 will completely react with (0.314 × 3) mol of CO
0.314 × 3 = 0.94 mol of CO
molar mass of CO = 12 + 16 = 28g/mol
mole = mass/molar mass
mass = mole × M.M
mass = 0.94 × 28
mass = 26.4g of CO
Answer:
B. Trees can be replenished
Explanation:
Trees are renewable and replenishable resources. Trees can be planted, grown up, and harvested for timber.
For a polar molecule<span>, your bonds will not cancel out. This means that in a </span>polar<span> bond, the electronegativity of the atoms will be different. For </span>nonpolar<span> bonds the electronegativity of the atoms will be equal. In a </span>polar<span> bond you will have an unequal sharing of electron pairs which causes a molecular dipole.</span>
Radon is the heaviest gas on Earth with a density of about 9.73 g/L. This is very high actually.
For more informations, radon is mostly used in radioactivity and cancer therapy.
Hope this Helps :)