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3 years ago

Divide the following rational expressions and simplify the result. -15/2k^5 ÷ 5/6k^5= ?

Mathematics

1 answer:

12345 [234]3 years ago

8 1

Answer:

-9

Step-by-step explanation:

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spayn [35]

Answer:

1360.78 g

Step-by-step explanation:

1 lb = 453.592 g

3 lbs = 3 * 453.592 g = 1360.78 g

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3 years ago

Please solve <br>y=2x(-1)+3

Korvikt [17]

First we multiply 2x*-1, which gives us -2x.

And that means the answer is y = -2x+3.

Hope this helped! c:

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3 years ago

TRUE or FALSE: Solon created the first true democracy

Sergeeva-Olga [200]

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Step-by-step explanation:

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3 years ago

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Answer:I need so much help with these two and quick if anybody can helpe out thanks.

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2 years ago

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

1 year ago

Divide the following rational expressions and simplify the result. -15/2k^5 ÷ 5/6k^5= ?​

Divide the following rational expressions and simplify the result. -15/2k^5 ÷ 5/6k^5= ?