12 because the formula for a circle is pi r^2 (h) and u get the circumference to get the diameter u just do it backwards
Answer:

Step-by-step explanation:
Given

Reflections: over y and x axis to create J"
Required
Determine J"
When reflected over y axis:

We have that:

So:

Hence

When reflected over x axis:

We have that:

So:

Hence

Its B cause the total amount needs to be 44.18 and the change 0.69x needs to be positive
Question: Perform the following computation with radicals. Simplify the answer. √6 • √8
Answer:

Step-by-step explanation:
Given, √6 • √8, to perform the computation, we would simply evaluate the radicals and try as much as possible to leave the answer in the simplest form in radicals.
Thus,



