1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergij07 [2.7K]
3 years ago
14

The following graph is a function

Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

<h2>True,,,. </h2>

it is the graph of a modulus function

Step-by-step explanation:

this may also be checked by vertical line test..

You might be interested in
PLEASE HELP!!!!!
Elodia [21]

Answer:

  A, D, E (probably preferred)

  B, C, F (also true)

Step-by-step explanation:

"This situation" problems are almost always ambiguous. The first problem is to figure out what it is about "this situation" that you want to model.

__

If we want to model concession stand revenue in a general way, then statements B, C, and F could represent "this situation." No specific values can be determined from this model.

__

More likely, we want to model the details of sales and revenue, so we want to know the exact numbers of water bottles and hamburgers that were sold. For "this situation," we can assign variables to the numbers of items of each type, and write equations for the total number of items and for the revenue their sales generates. Appropriate statements about this interpretation of the problem are those of A, D, and E:

  A: x could represent bottles sold

  D: y could represent hamburgers sold

  E: The system of equations could be 2.50x +5.50y = 1325; x +y = 350.

_____

The solution to the last model is 200 bottles were sold for revenue of $500, and 150 hamburgers were sold for revenue of $825.

6 0
3 years ago
Read 2 more answers
Pls someone anwser quick
sergejj [24]
Letter “F” Po
Sure yan
7 0
3 years ago
After reading 80\%80% of her e-mails in her inbox, Danette still has MM unread e-mails.
NARA [144]

Answer:   <em>The correct options are.....</em>

<em>A)   \frac{M}{1-0.8}   and</em>

<em>B)   5M</em>

Step-by-step explanation:

Suppose, the number of e-mails Danette had in her inbox before she started reading was X.

Percentage of read emails is 80%, so the number of read emails = (\frac{80}{100}*X)=0.8X

<u>Thus, the number of unread emails</u> = X-0.8X=X(1-0.8), <u>which is given as</u> M.

So, the equation will be........

X(1-0.8)=M\\ \\ \Rightarrow X=\frac{M}{1-0.8} (Answer: 1) \\ \\ \Rightarrow X=\frac{M}{0.2}\\ \\ \Rightarrow X=(\frac{1}{0.2})M=5M (Answer: 2)

Thus, the expressions which could represent the number of e-mails Danette had in her inbox before she started reading are:  \frac{M}{1-0.8} or 5M

3 0
4 years ago
When rabbits were introduced to the continent of Australia they quickly multiplied and spread across the continent since there w
Lady bird [3.3K]

Answer:

a. y=6(1.7472)^x

b. y=6e^{0.558t}

c.13.3 months

Step-by-step explanation:

a.-Given the first term  at t_0 is 6 and the second term at t_3 is 32.

-Let's take rabbit population as a function of time to be

y=ab^x

where y is the population at time x and a the initial population at t_0\\

#We substitute our values to calculate the value of the constant b:

y_x=ab^x\\\\y_3=ab^3\\\\32=6b^3\\\\b=1.472

#Replace b in the population function:

y=ab^x, b=1.7472,a=6\\\\\therefore y=6(1.7472)^x

Hence, the regression for the rabbit population as a function of time x is y=6(1.7472)^x

b. The exponential function in terms of base e is usually expressed as:

A=A_0e^{kt}

Where:

A_0-is the initial population at t_o

A-is the population at time t.

k-is the  exponential growth constant.

e- the exponent

Our function in terms of base exponent is rewritten as:

y=A_0e^{kt}

#Substitute with actual figures to solve for t:

y=A_0e^{kt}, y=32, xt=3, A_0=6\\\\32=6e^{3k}\\\\3k=In (32/6)\\\\k=0.5580

Hence, the regression equation in terms of base e is y=6e^{0.558t}

c. We substitute y with any number higher than 10,000 to estimate the time for the rabbits to exceed 10,000.

-We know that y=6e^{0.558t}.

Therefore we calculate t as(take y=10001):

y=6e^{0.558t}, y=10001\\\\10001=6e^{0.558t}\\\\1666.8333=e^{0.558t}\\\\0.558t= In 1666.8333\\\\t=13.2951

Hence, it takes approximately 13.3 months for the population to exceed 10000

3 0
4 years ago
HELPPPPPP!!!!!!!!!!!!!!!
Katarina [22]

Answer:

I might be wrong i think its C but double check and dont put it in until you are sure its right

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • 1/3 of the fish in the tank are snappers. 2/9 of the fish are catfish and the rest are goldfish. There are 40 goldfish in the ta
    9·2 answers
  • Answer asappppp please
    6·1 answer
  • Write the prime factorization of these numbers 18
    7·1 answer
  • Rotation of 120 degrees. please help!
    11·1 answer
  • I'm doing domain and range, and I'm kinda having a hard time with this... can someone help?
    11·2 answers
  • A bag contains 8 green M&amp;Ms, 12 blue M&amp;Ms, and 2 orange M&amp;Ms. What is the
    11·1 answer
  • X+2x + ___=5x. What goes on the blank
    11·1 answer
  • Help!! will give brainl.ly &lt;3
    10·1 answer
  • A pool has a length that is 3 times the width. Write the algebra radical value of the corner to corner distance
    7·1 answer
  • The angle of depression at a point on the ground from the top of a building is 60°. If the point is 36m far from the foot of the
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!