(3^0-(3^2)^3)/9^3
3^0=1
3^2=(3*3)=9->9^3=(9*9*9)=729
1-729=-728
9^3=(9*9*9)=729
-728/729
Answer:
36
Step-by-step explanation:
you add the first two the order of operations then you do big and little
Answer:
m<ABC = 100degrees
m<IJG = 104degrees
Step-by-step explanation:
14. The sum of the opposite angle of the quadrilateral is 180degrees. Hence;
m<ADC + m<ABC = 180
3y+8+4y+4 = 180
7y + 12 = 180
7y = 180 - 12
7y = 168
y = 168/7
y = 24
Get <ABC
m<ABC = 4y+4
m<ABC = 4(24) + 4
m<ABC = 96 + 4
m<ABC = 100degrees
15. Similarly for this;
GHI + IJG = 180
76 + m<IJG = 180
m<IJG = 180 - 76
m<IJG = 104degrees
