What is the minimum number of binary bits needed to represent each of the following unsigned decimal integers? a. 65
2 answers:
Answer: N >/= 7 bits
Minimum of 7 bits
Step-by-step explanation:
The minimum binary bits needed to represent 65 can be derived by converting 65 to binary numbers and counting the number of binary digits.
See conversation in the attachment.
65 = 1000001₂
65 = 7 bits :( 0 to 2^7 -1)
The number of binary digits is 7
N >/= 7 bits
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Answer:
see explanation
Step-by-step explanation:
The n th term of a geometric progression is
• = a₁
where a₁ is the first term and r the common ratio
given a₄ = 24, then
a₁ = 24 → (1)
Given a₈ = , then
a₁ =
→ (2)
Divide (2) by (1)
=
=
Hence r = =
Substitute this value into (1)
a₁ × ( )³ = 24
a₁ × = 24, hence
a₁ = 24 × 27 = 648