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1 year ago

8

ABCD is a quadrilateral and a line through A parallel to BC meets DC at X. If angle D=angle C , prove that ADX is isosceles.

1 answer:

r-ruslan [8.4K]1 year ago

7 0

Answer:

see picture below

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Wich hotel costs the least per night ? :)

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Answer:

answer b

step - by - step explanation

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What is the length of the cylinder's height? Please help

raketka [301]

Answer:

Height = <u>9</u><u> </u>cm which means <u>Option </u><u>C </u>is the answer

Step-by-step explanation:

In the question we are given ,

Volume of cylinder = <u>2</u><u>2</u><u>5</u><u>π</u><u> </u><u>cm³</u>

Radius of cylinder = <u>5 cm</u>

And , we have to find the <u>height</u><u> of</u><u> </u><u>cylinder</u><u> </u>.

We know that ,

$\longrightarrow \pink{ \boxed{Volume \: of \: Cylinder = \pi r {}^{2}h }} \longleftarrow$

Our solution starts from here :

$\longmapsto \: \pi \: r {}^{2} h = 225\pi$

<u>Step </u><u>1</u><u> </u><u>:</u> Cancelling π with π :

$\longmapsto \: \cancel{\pi} \: r {}^{2} h = 225 \cancel{\pi}$

<u>Step </u><u>2</u><u> </u><u>:</u> Substituting value of radius which is 5 cm in the formula :

$\longmapsto \: (5) {}^{2} \times h = 225$

$\longmapsto \: 25h = 225$

<u>Step </u><u>3 </u><u>:</u> Transposing 25 to right hand side :

$\longmapsto \: h = \frac{225}{25}$

<u>Step </u><u>4</u><u> </u><u>:</u> Cancelling 225 by 25 :

$\longmapsto \: \red{\boxed{h = 9 \: cm}}$

<u>Henceforth</u><u> </u><u>,</u><u> </u><u>height</u><u> </u><u>of </u><u>cylinder</u><u> is</u><u> </u><u>9</u><u> </u><u>cm</u>

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