What is the surface area of the pyramid? 3 6

Jika 5log2 = x dan 5log6 = y, maka nilai 4log150 adalah

icang [17]

Menjawab:

y + 2x

Penjelasan langkah demi langkah:

Menulis ulang pertanyaannya

4log5 = x

4log 6 = y

4 log 150 = 4log (2 * 3 * 5 * 5)

= 4log 6 + 4log 5 + 4log 5

Substrat

= y + x + x

= y + 2x

Oleh karena itu ekspresi yang dibutuhkan adalah y + 2x

7 0

3 years ago

Evaluate the following expression if a=-9, b=-7,c=9 and d=3<br> 2cd + 3ab =

stepladder [879]

Answer:

<h3>The answer is 243.</h3>

Step-by-step explanation:

To evaluate the expression substitute the values of a , b , c and d into the above expression

a = - 9

b = - 7

c = 9

d = 3

So we have

2cd + 3ab = 2(9)(3) + 3(-9)(-7)

= 2(27) + 3( 63)

= 54 + 189

We have the final answer as

Hope this helps you

7 0

3 years ago

A population of mice is increasing exponentially. On Monday there were 120 most. One month later there were 132 most. Ready func

djyliett [7]

Answer:

$y=120 * 1.1^x$ --- function

The monthly rate is 10%

Step-by-step explanation:

Given

Let

$x \to months$

$y \to mice$

So, we have:

$(x_1,y_1) = (0,120)$ --- Monday

$(x_2,y_2) = (1,132)$ --- One month later

Required

The function

The function is represented as:

$y=ab^x$

In $(x_1,y_1) = (0,120)$ , we have:

$120 = a * b^0$

$120 = a * 1$

$120 = a$

$a=120$

In $(x_2,y_2) = (1,132)$ , we have:

$132 = a * b^1$

$132 = a * b$

Substitute: $a=120$

$132 = 120 * b$

Solve for b

$b = \frac{132}{120}$

$b = 1.1$

So, the function is:

$y=ab^x$

$y=120 * 1.1^x$

To calculate the monthly rate (r), we have:

$y =a(1 + r)^x$

Compare to: $y =ab^x$

$1 + r = b$

Make r the subject

$r = b-1$

Substitute $b = 1.1$

$r = 1.1-1$

$r = 0.1$

Express as percentage

$r = 0.1*100\%$

$r = 10\%$

5 0

2 years ago

What is the prime factorization of 96?<br> 0 25.32<br> 25.3<br> 02.2.2.2.3<br> 8.12

Nina [5.8K]

Answer:

8.12

Step-by-step explanation:

we first multiply 8 by 12 and we will get 96 as our answer

7 0

3 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

2 years ago

What is the surface area of the pyramid? 3 6​

What is the surface area of the pyramid? 3 6