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DanielleElmas [232]

2 years ago

8

A TV has a listed price of $900.99 before tax. If the sales tax rate is 6.75%, find the total cost of the TV with sales tax incl

uded.
Round your answer to the nearest cent, as necessary.

1 answer:

Marta_Voda [28]2 years ago

6 0

$900.99 x 6.75% = 60.82 (tax)
$900.99 + $60.82 = $961.81 total cost.

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A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l

ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>

6 0

2 years ago

A system of equations is shown below.

EastWind [94]

Multiply equation B by 3 and add the result to

equation A.

4 0

3 years ago

What is the value of 1+(-7)-(-2.5)?

adell [148]

Step 1: remove parentheses
1-7+2.5
step 2:simplify 1-7 to -6
-6+2.5
step 3 :simplify
-3.5
the answer is -3.5

4 0

3 years ago

Military radar and missile detection systems are designed to warn a coutry of an enemy attack. Assume that a particular detectio

Tom [10]

Answer:

0.96 = 96% probability that at least one of them detect an enemy attack.

Step-by-step explanation:

For each radar, there are only two possible outcomes. Either it detects the attack, or it does not. The missiles are operated independently, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that a particular detection system has a 0.80 probability of detecting a missile attack.

This means that $p = 0.8$

If two military radars are installed in two different areas and they operate independently, the probability that at least one of them detect an enemy attack is

This is $P(X \geq 1)$ when $n = 2$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.8)^{0}.(0.2)^{2} = 0.04$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.04 = 0.96$

0.96 = 96% probability that at least one of them detect an enemy attack.

6 0

3 years ago

Mike weighs 24 more pounds than Mark. Together, they weigh 250 pounds. How many do they each weigh?

djverab [1.8K]

To get your answer, follow my method :

First you take away 24 from 250=226
Then you half 226=113 which is Mark's weight
As Mike weights 24 pounds more that Mark, you have to add 24 back=137
So your answer is :
Mark weights 113 pounds and Mike weights 137 pounds.

6 0

3 years ago