Answer:
y = x
Step-by-step explanation:
The slopes of parallel lines are the same, so we know the equation will be ...
y = x + constant
We can find the constant by using the given point's values for x and y:
2 = 2 + constant
Obviously, the constant is zero.
The equation of the parallel line through (2, 2) is y = x.
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has CDF
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where

is the CDF of
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. Since

are iid. with the standard uniform distribution, we have
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and so

Differentiate the CDF with respect to

to obtain the PDF:

i.e.

has a Beta distribution

.
A stem and leaf plot shows sets of two digit numbers, by separating the ten’s place and the one’s place. On the left is the different ten’s values, while on the right next to each of the values on the left is the one’s values that associate with each of the ten’s values. This means that the numbers in this set of data are 32, 47, 51, 55, 55, 55, 58, 64, and so on. From there, you can use that knowledge to figure out how many scores were above 60.
The terms that are above 60 are 64, 65, 73, 74, 77, 87, 88, 91, 93, 93, 97, 99, and 99, for a total of 13 of the 20 scores being above 60.
Answer:
first answer is correct
Step-by-step explanation:
Hello, we want to write 2 + 4 + 6 + ... + 20
for n = 1, 2n = 2*1 =2
for n = 2, 2n = 2*2=4
for n = 3, 2n=2*3=6
etc
so

thanks