If it soaks into the earths surface it becomes ground water
Acceleration = (change in speed) / (time for the change)
Change in speed = (speed at the end) - (speed at the beginning).
Change in speed = (10 m/s) - (zero) = 10 m/s
Time for the change = 3 sec
Acceleration = (10 m/s) / (3 sec)
<em>Acceleration = (3 and 1/3) m/s²</em> or 3.333 m/s²
Answer:
40.1m/s
Explanation:
This is a kinematics problem
x = 82m
a = -9.8m/s^2
v(initial) = 0
Find: v(final)
Using kinematics equation:
vf^2 = vi^2 + 2a(delta)x
vf^2 = 0 + 2*(-9.8)*(82)
vf = sqrt(1607.2) = 40.09m/s
The is traveling with a velocity of 40.1m/s when it hits the ground.
