Exertion is not a good way to describe exercise but there is also alot more words to describe wrong ways for exercise
Answer:
The reading of the scale during the acceleration is 446.94 N
Explanation:
Given;
the reading of the scale when the elevator is at rest = your weight, w = 600 N
downward acceleration the elevator, a = 2.5 m/s²
The reading of the scale can be found by applying Newton's second law of motion;
the reading of the scale = net force acting on your body
R = mg + m(-a)
The negative sign indicates downward acceleration
R = m(g - a)
where;
R is the reading of the scale which is your apparent weight
m is the mass of your body
g is acceleration due to gravity, = 9.8 m/s²
m = w/g
m = 600 / 9.8
m = 61.225 kg
The reading of the scale is now calculated as;
R = m(g-a)
R = 61.225(9.8 - 2.5)
R = 446.94 N
Therefore, the reading of the scale during the acceleration is 446.94 N
Answer:
Explanation:
An object is thrown up from a height of 520m
h_o = 520m
Initial velocity of thrown is 18m/s
u = 18m/s
What is the position of the object after 3seconds
t = 3s
Acceleration due to gravity
g = 9.81 m/s²
Let calculated the height the object will reached when thrown from the top.
Using equation of motion
h = ut + ½gt²
Since the body is thrown upward, it is acting against gravity then, gravity will be negative
Then,
h = ut — ½gt²
h = 18 × 3 — ½ × 9.81 × 3²
h = 54 — 44.145
h = 9.855 m
So, the body is above the top of the building at a distance of 9.855m
So, the total distance from the bottom is
Position = h + h_o
x = 9.855 + 520
x = 529.855m
x ≈ 530m,
The position of objects after 3seconds is 520m
The answer is going to be 40
