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3 years ago

3. In dividing 12m2 - 20m + 3 by 2m - 3, what is the first step?

Mathematics

1 answer:

harina [27]3 years ago

7 0

Answer:

by dividing answer is 6m-1

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(08.07A LC)

shtirl [24]

Answer:

Step-by-step explanation:

you would do the total which is 45-20

5 0

3 years ago

Let f(x) = x + 7 and g(x) = x − 4. Find f(x) ⋅ g(x). (1 point) x2 − 3x −28 x2 − 3x − 11 x2 + 3x − 28 x2 + 3x − 11

slavikrds [6]

$f(x)=x+7\\g(x)=x-4\\f(x)*g(x)=(x+7)(x-4)\\f(x)*g(x)=x^2+3x-28$

So it's x^2+3x-28

3 0

3 years ago

Suppose x is any positive number. Circle 1 has a center at (−2, 7) and a radius of 8x. Circle 2 has a center at (−3, 0) and a ra

aniked [119]

The correct answer is C.
Circle 1 has radius 8x. Circle 2 has radius 5x.
8x/5x = 1.6
Circle 1 is a dilation of Circle 2 with a scale factor of 1.6.
The radius of Circle 1 is 1.6 times greater than the radius of Circle 2.

6 0

3 years ago

At the arcade, Sami won 2 blue tickets, 1 yellow ticket, and 3 red tickets for 1500 total points. Jamie won 1 blue ticket, 2 yel

aleksandrvk [35]

Answer:

$\left[\begin{array}{ccc}2&1&3\\1&2&2\\2&3&1\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}1500&1225&1200\end{array}\right]$

Step-by-step explanation:

Given

$b = blue$

$y = yellow$

$r = red$

Required

Represent as a matrix

For Sammy:

$2\ blue + 1\ yellow + 3\ red =1500$

So, we have:

$2b + 1y + 3r = 1500$

$2b + y + 3r = 1500$

For Jamie:

$1\ blue + 2\ yellow + 2\ red =1225$

So, we have:

$1b + 2y + 2r = 1225$

$b + 2y + 2r = 1225$

For Yvonne:

$2\ blue + 3\ yellow + 1\ red =1200$

So, we have:

$2b + 3y + 1r = 1200$

$2b + 3y + r = 1200$

The system of equations are:

$2b + y + 3r = 1500$

$b + 2y + 2r = 1225$

$2b + 3y + r = 1200$

To represent as a matrix, we have:

$\left[\begin{array}{ccc}b_1&y_1&r_1\\b_2&y_2&r_2\\b_3&y_3&r_3\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}Total_1&Total_2&Total_3\end{array}\right]$

This gives:

$\left[\begin{array}{ccc}2&1&3\\1&2&2\\2&3&1\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}1500&1225&1200\end{array}\right]$

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3 years ago

Someone help me with this Alegerbratic expression. Really hard 10 questions.

Nady [450]

Hi!!! yall's are so cute! I love iron man wish you the best!

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3 years ago