Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
The answer is 12 percent change
A. x <= -12
<u>Explanation:</u>
-3x >= 36
-x >= 36/ 3
-x > = 12
x < = -12
When the negative sign is shifted then the greater than equal to sign reverses to less than equal to.
Therefore, x <= -12
Well A should be congruent to S because (Base Angles Therom)
A =S
