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3 years ago

Help me pleeeeeeeeeeease

Mathematics

2 answers:

andrew11 [14]3 years ago

8 0

I think it’s 3 because of y=mx+b so the right answer would be 3

erastovalidia [21]3 years ago

6 0

Answer:

Step-by-step explanation:

If Andre's representation is correct, that the slope is 3. The question is confusing me a bit, because it isn't very clear, but Andre's Representation is in Point Slope Form, (y=mx+b) where m represents the slope. So again, if Andre's representation is for the graph and is correct, the slope is 3.

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2 years ago

Given:<br> f(x)=x^2<br> g(x)=x-1<br> Find f(g(2))+g(f(-1))

Fittoniya [83]

Answer:

Step by step explanation:

$\text{Given that,} ~ f(x) = x^2~ \text{and}~ g(x) = x-1\\\\g(2) = 2-1 = 1\\\\g(f(-1)) = g(1) = 1-1 = 0\\\\f(g(2) + g(f(-1)))= f(1+0) = f(1) = 1^2 =1$

6 0

3 years ago

Read 2 more answers

The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?

denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

$PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5$

All sides have the same lengths.

2. Find the slopes of all lines:

$PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}$