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3 years ago

What mass (in g) of potassium chlorate is required to supply the proper amount of oxygen needed to burn 117.3 g of methane

1 answer:

7 0

The mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

<h3>Combustion of methane</h3><h3 />

Methane burns in oxygen to produce carbon (iv) oxide and water according to the equation of the reaction below:

CH₄ + 2O₂ ----> CO₂ + 2H₂O

1 mole of methane requires 2 moles of oxygen for complete combustion

1 mole of methane has a mass of 16 g

moles of methane in 117.3 g = 117.3/16 = 7.33 moles of methane

7.33 moles of methane will require 2 * 7.33 moles of oxygen

7.33 moles of methane will require 14.66 moles of oxygen

<h3>Decomposition of potassium chlorate </h3>

The decomposition of potassium chlorate produces oxygen

The equation of the reaction is given below:

2KClO3 → 2KCl + 3O2.

2 moles of potassium chlorate produces 3 moles of oxygen

14.66 moles of oxygen will be produced by 14.66 * 2/3 moles of potassium chlorate

14.66 moles of oxygen will be produced by 9.77 moles of potassium chlorate

1 mole of potassium chlorate has a mass of 122.5

9.77 moles of potassium chlorate has a mass of 1196.82 g

Therefore, the mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

Learn more about mass and molar mass at: brainly.com/question/15476873

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Daniel [21]

Answer:

a. 2nd order reaction.

b. The first step is the slow step.

Explanation:

r = k[NO][Cl₂]

a. The reaction is first-order in [NO] and first-order in [Cl₂], so it is second-order overall.

b. The first step is the slow step, because it predicts the correct rate law.

c. is wrong. Doubling [NO] would double the rate, because the reaction is first-order in [NO].

d. is wrong. Cutting [Cl₂] in half would halve the rate, because the reaction is first-order in [Cl₂].

e. is wrong. The molecularity is two, because two particles are colliding.

f. is wrong. Both steps are bimolecular.

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4 years ago

Where glucose is broken down into smaller molecules to produce energy. The second part of the process takes place in the

slavikrds [6]

Answer:

Mitochondria

Explanation:

Glucose in an energy molecule contained in carbohydrate food substances. The end product of the digestion of carbohydrate is glucose which is broken down to produce energy.

The sequence of breakdown of glucose is as follows; In the first step, 6-carbon glucose is broken down into two molecules of 3-carbon pyruvic acid. This occurs in the cytoplasm of the cell. It is an anaerobic process.

In the second step which occurs in the mitochondrion, each of the molecules of pyruvic acid is now oxidized to carbon dioxide and water and energy is produced in the process.

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3 years ago

Question 1 (3 points)

den301095 [7]

Answer:

Explanation:

ΔTemp => 35⁰C(108K) increases to 57.9⁰C(330.9L) => increases volume (Charles Law)

Use the Kelvin Temperature values in a ratio that will increase the original volume.

ΔVol = 6.33L(330.9/108.0) => gives a larger volume. Using 108.0/330.9 would give a smaller volume and would be contrary to what the problem is asking.

ΔPress => 342 mmHg increases to 821 mmHg => decreases volume (Boyles Law)

Use the pressure values in a ratio that will decrease the original volume.

ΔPress = 6.33L(342/821) => gives a smaller volume. Using 821/342 would give a larger volume and would be contrary to what the problem is asking.

Now, putting both ΔTemp together with ΔPress => net change in volume. (Combined Gas Law)

ΔVol = 6.33L(330.9/108.0)(342/821) = 8.08L (final volume of gas).

___________________

This problem can also be worked using the combined gas law equation:

P₁V₁/T₁ = P₂V₂/T₂ => V₂ = P₁V₁T₂/T₁P₂

V₂ = [(342mm)(6.33L)(330.9K)]/[(108K)(821mm)] = 8.08L (final volume of gas)

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3 years ago

How many mg of calcium are present in a 500-mg tablet of calcium carbonate??

Setler79 [48]

The molar mass of calcium carbonate is 100 mg/mmol, so the number of moles is:

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We see that there is 1 mole of Ca per 1 mole of CaCO3, therefore:

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3 years ago

A student compares the boiling point of substances having different intermolecular forces. which dependent variable did the stud

Gwar [14]

A student compares the boiling point of substances having different intermolecular forces. <u>Boiling points of various substances</u> is the dependent variable that student most likely use.

<h3>Does the nature of intermolecular forces present in different substance affect their boiling points?</h3>

The boiling point of a substance is proportional to the strength of its intermolecular forces, the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.

<h3>What properties are affected by intermolecular forces?</h3>

Intermolecular forces are measured by boiling points.

Intermolecular forces increase as bond polarization increases.

Ionic > hydrogen bonding > dipole dipole > dispersion is the order of the strength of intermolecular forces (and thus their impact on boiling points).

<h3>How can you determine strong and weak intermolecular forces?</h3>

Substances with strong intermolecular forces are very attracted to one another and are held together tightly. These substances require a great deal of energy to separate, whereas substances with weak intermolecular forces are held together very loosely and have weak interactions.

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