The equation for the reaction is
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The structure of Methanol (CH₃OH) is shown below. This structure contains 2 lone pair of electrons on oxygen (highlighted red). Electronic configuration of oxygen is,
Oxygen = 8 = 1s², 2s², 2px², 2py¹, 2pz¹
There are six electrons in valence shell of oxygen, among these six electrons two electrons are unpaired and involved in forming covalent bond with hydrogen and carbon, while remaining 4 electrons in pair (i.e. 2s², 2px²) exists as lone pairs.
Oxygen = 8 = 1s², 2s², 2px², 2py¹, 2pz¹
There are six electrons in valence shell of oxygen, among these six electrons two electrons are unpaired and involved in forming covalent bond with hydrogen and carbon, while remaining 4 electrons in pair (i.e. 2s², 2px²) exists as lone pairs.