<span>equilibrium constant times the concentration of water. - 100% guaranteed correct</span>
Answer:
Molar mass of monoprotic acid is 1145g/mol.
Explanation:
The reaction of a monoprotic acid (HX) with NaOH is:
HX + NaOH → H₂O + NaX
That means 1 mole of acid reacts with 1 mole of NaOH
If the neutralization of the acid spent 20.27mL of a 0.1578 M NaOH solution. Moles of NaOH are:
0.02027L × (0.1578mol / L) = <em>3.199x10⁻³ moles</em> NaOH ≡ moles HX.
As mass of the sample is 3.664g, molar mass of the acid is:
3.664g / 3.199x10⁻³ moles =<em> 1145g/mol</em>
Answer is b..............…
