a. 30 moles of H₂O
b. 2.33 moles of N₂
<h3>Further explanation</h3>
Given
a. 20 moles of NH₃
b. 3.5 moles of O₂
Required
a. moles of H₂O
b. moles of N₂
Solution
Reaction
4NH₃+3O₂⇒2N₂+6H₂O
a. From the equation, mol ratio NH₃ : H₂O = 4 : 6, so mol H₂O :
=6/4 x mol NH₃
= 6/4 x 20 moles
= 30 moles
b. From the equation, mol ratio N₂ : O₂ = 2 : 3, so mol N₂ :
=2/3 x mol O₂
= 2/3 x 3.5 moles
= 2.33 moles
The molar mass of PH3 is 34 g/mol, therefore the moles
is:
moles PH3 = 225 g / (34 g/mol)
moles PH3 = 6.62 mol
The balanced equation is:
4PH3(g) + 8O2(g) → P4O10(g) + 6H2O
We see that 4 mol of PH3 is required for every mol of
P4O10, therefore the number of moles of P4O10 is:
moles P4O10 = 6.62 mol * (1/4)
moles P4O10 = 1.65 mol
The molar mass of P4O10 is 283.89 g/mol, so the mass is:
mass P4O10 = 1.65 mol * 283.89 g/mol
mass P4O10 = 469.67 grams ~ 470 grams
Transition metals are less reactive than alkali metals because of their high ionization potential and high melting point.
On moving from left to right of the periodic table for every period, electrons fill in the same shell or orbital, with the alkali metals having the least filled outermost shells, one electron, which equates to fewer protons in them.
Consequently, they have a lesser attraction power from the nucleus, whereas, the corresponding transition metals of the same period have more protons interacting with electrons at the same distance, far from the nucleus as the alkali metals.
Answer is: d) Hg.
Mercury is a chemical element with the symbol Hg and atomic number 80. <span> Mercury is the only metallic element that is liquid at standard conditions for temperature and pressure.
</span>Absolute viscosity of mercury is 0,0015 Pa·s.
The viscosity<span> of a </span>fluid<span> is a measure of its </span>resistance<span> to gradual deformation by </span>shear stress<span> or </span><span>tensile stress</span>
