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2 years ago

What is the salon to the equation? 15 = |x| - 5

Mathematics

2 answers:

earnstyle [38]2 years ago

5 0

Step-by-step explanation:

15 = |x| - 5

|x| - 5 = 15

|x| = 15 + 5

|x| = 20

x = ±20

x = -20 or 20

Option → B

Alla [95]2 years ago

3 0

$\huge\text{Hey there!}$

$\large\boxed{\mathsf{15 = |x| - 5}}\\\large\boxed{\mathsf{|x| - 5 = 15}}\\\large\boxed{\textbf{ADD 5 to BOTH SIDES}}\\\large\boxed{\mathsf{\rightarrow |x| - 5 + 5 = 15 + 5}}\\\large\boxed{\textbf{CANCEL out: -5 + 5 because it gives you 0}}\\\large\boxed{\textbf{KEEP: 15 + 5 because it help solve for the x-value}}\\\large\boxed{\textbf{NEW EQUATION: }\mathbf{|x| = 15 + 5}}\\\large\boxed{\textbf{SIMPLIFY IT!}}\\\large\textbf{Possibility \#1: x = 20}\\\large\textbf{or even Possibility \#2: x = -20}$

$\huge\textbf{Therefore, your answer is: }\\\boxed{\mathsf{x = 20\ or\ x = -20}}\\\huge\boxed{\textbf{(Option B.)}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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xenn [34]

Answer:

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Explanation:

m∠2 = 130° because of alternate exterior angles.

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miss Akunina [59]

Hey there!!

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2 years ago

Read 2 more answers

B) Write 25 x 10° in standard form.

xz_007 [3.2K]

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2 years ago

The product of a binomial and trinomial is x^3+3x^2-x+2x^2+6x-2 which expression is equivalent to this product after it has been

Debora [2.8K]

Answer: First option.

Step-by-step explanation:

You know that the product obtained by multiplying a binomial and a trinomial is:

$x^3+3x^2-x+2x^2+6x-2$

Then, in order to simplify this product, it is necessary to add the like terms.

Therefore, the expression that is equivalent to this product after it has been fully simplified is:

$=x^3+(3x^2+2x^2)+(6x-x)-2\\\\=x^3+5x^2+5x-2$

You can observe that this matches with the first option.

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2 years ago

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : <em>[ $x^{2}$ + 3x + 3 ] =0 </em>

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3 years ago