Answer:
The correct answer should be y > -1 and y < -6. So the graph should show an open dot at -1 with an arrow pointing to the right. It should also show a open dot at -6 with an arrow pointing to the left.
Step-by-step explanation:
To find this, we need to split this into two different equations. The first one we solve by just removing the absolute value brackets.
4y + 16 < 12
4y < -4
y < -1
The second way is by switching the symbol's direction and negating the answer. This is because of the absolute value symbols.
4y + 16 > -12
4y > -28
y > -6
Answer:
1/13
Step-by-step explanation:
This is like 7 - 6 since the denominator is the same.
Answer: 64
Step-by-step explanation: just 64
Answer:
84.6
Step-by-step explanation:
135c + 273.15 = 408 K
72C + 273.15 = 345 K
100 L over 408 K = V2 over 345 K
V2= 84.6
Well that depends if his exam board rounds his percentage up, lol.
So Bhavik needs 93% to get a level 9.
I'm going to assume that he got 89% on both his papers, (but it could be any two numbers that average to give 89%, e.g. 88% and 90%.)
Assuming that he gets 100% for his last paper (which is very unlikely), the mean value would be (89% + 89% + 100%) ÷ 3 = 92.67%.
92.67% isn't quite 93%, and it's also very unlikely for him to get 100% on his last paper (when you take the results of his last two papers in to consideration).
So the answer is no, it's not possible for him to achieve a top grade overall. He's going to have to stick with a level 8.
