Answer:
see explanation
Step-by-step explanation:
let pq = x
given oq - pq = 1 then oq = 1 + x
Using Pythagoras' identity, then
(oq)² = 7² + x²
(1 + x)² = 49 + x² ( expand left side )
1 + 2x + x² = 49 + x² ( subtract 1 from both sides )
2x + x² = 48 + x² ( subtract x² from both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ⇒ pq = 24
and oq = 1 + x = 1 + 24 = 25 ← hypotenuse
sinq = 
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cosq = 
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Answer:
yea by using a resipe
Step-by-step explanation:
Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0
Discriminant = 4 - 4(K)(-1) = 4 + 4K
For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.
The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.
Answer:
18√2
Step-by-step explanation:
2√18 + 3√2 + √162
= 2√(9 * 2) + 3√2 + √(81 * 2)
= (2 * 3)√2 + 3√2 + 9√2
= 6√2 + 3√2 + 9√2
= (6 + 3 + 9)√2
= 18√2
