All categories

3 years ago

2/9 divided by 2/3 is??????

Mathematics

1 answer:

geniusboy [140]3 years ago

4 0

Step-by-step explanation:

$\tt{} \frac{2}{9} \div \frac{2}{3}$

$\tt{} \frac{2}{9} \times \frac{3}{2}$

$\tt{} \frac{1}{3} \times \frac{1}{1}$

$\tt{} \frac{1 \times 1}{3 \times 1}$

$\tt{} \frac{1}{3}$

You might be interested in

PLZ HELP NOW PLZ PLZ

anyanavicka [17]

Answer:

16ft i think

Step-by-step explanation:

7 0

3 years ago

2 less than the product of 5 and n

Deffense [45]

The product of 5 and n is written as $5n$ .

Two less than this product is $5n-2$

7 0

3 years ago

Jesse worked forty hours this past week assuming he makes $12 an hour how much was withheld from his paycheck by his employer fo

Alecsey [184]

He made 12*40=480 dollars in total. 0.0765*480=36.72 dollars were withheld.

6 0

3 years ago

Read 2 more answers

How to multiply and divide integers

Artyom0805 [142]

You multiply or divide integers just as you do whole numbers, except you must keep track of the signs. To multiply or divide signed integers, always multiply or divide the absolute values and use these rules to determine the sign of the answer.

When you multiply two integers with the same signs, the result is always positive. Just multiply the absolute values and make the answer positive.

Positive x positive = positive
Negative x negative = positive

When you multiply two integers with different signs, the result is always negative. Just multiply the absolute values and make the answer negative.

Positive x negative = negative
Negative x positive = negative

When you divide two integers with the same sign, the result is always positive. Just divide the absolute values and make the answer positive.

Positive ÷ positive = positive
Negative ÷ negative = positive

When you divide two integers with different signs, the result is always negative. Just divide the absolute values and make the answer negative.

Positive ÷ negative = negative
Negative ÷ positive = negative

6 0

3 years ago

Read 2 more answers

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

3 years ago