Answer: A.
Explanation:
Cells generally have a relatively short lifestyle in that they grow, divide and then die off. This is not the case with cancerous cells as those ones mutate and then multiply such that they eventually form a tumor.
Looking at the graph, most of the cells are remaining at a lower or manageable number because they are dying off. Cell A on the other hand is simply increasing in number which means that it is a cancerous cell as it is increasing its number by mutating instead of dying off like other cells would.
Studying animals in the wild is considered somewhat experimentally out of control because of several reasons.
<u>Explanation:</u>
Study of wild animals can be done using several methods but none will be as effective as studying captivated animals. Using stationary cameras is a method to observe animals in the wild. The stationary nature of the camera makes it necessary for the animals to appear within the field of the camera.
This is difficult in places of low animal density. In addition to that placing camera at a longer distance to watch a larger area decreases the resolution of the images. When it comes to shallow water systems, the field imagery used to track the aquatic species frequently gets affected by issues like sun flicker.
Unmanned aerial vehicles can also be used to track and study animals in the wild. This is good alternative but filming through dense canopies or turbid water is a limitation. Bio loggers can also be used for animal tracking but it is limited by weight since it has to be carried by animals.
For full activation of a cyclin-CDK complex, an enzyme called CDK-activating kinase must phosphorylate an amino acid near the CDK active site.
CDK-activating kinase (CAK) actuates the cyclin-CDK complex by phosphorylation of an amino acid i.e. threonine residue 160 near the CDK active site.
CAK is a member of the CDK family and serves as a positive regulator of CDK1, CDK2, CDK4, as well as CDK6.
CDK activation needs two steps. Primarily, the cyclin should attach to the CDK and secondly, CAK should phosphorylate the cyclin-CDK complex on the threonine residue 160, that is situated in the CDK activation section.
To learn more about cyclin here
brainly.com/question/13327301
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Answer:
In passive transport, substances move from an area of higher concentration to an area of lower concentration. Diffusion through a permeable membrane moves a substance from an area of high concentration (extracellular fluid, in this case) down its concentration gradient (into the cytoplasm).
Explanation:
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Answer:
i can not help you with that sorry
Explanation:
