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marusya05 [52]
2 years ago
7

Solve the math problem

Mathematics
1 answer:
Colt1911 [192]2 years ago
6 0

Answer:I think its ether y-interspersed or equation

Step-by-step explanation:

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Where does the line y=3x-5 cross the y axis?
makkiz [27]

Answer:

At (0, -5)

Step-by-step explanation:

The y-intercept (b) is -5 (<em>slope intercept form: y = mx + b</em>) the line will thus cross the y axis at the point (0, -5).

7 0
2 years ago
Mark and a friend went out for dinner the bill was $23.40 they leave a 20% tip how much of a tip will they leave ? ​
natita [175]

Answer:

answer is 4.68$

Step-by-step explanation:

23.40×20/100=4.68

4.68$ is 20% of 23.40$

4.68$

8 0
3 years ago
Factor 6y + 8y 6y² +8y?​
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Answer:uiuyiuytghjv 312

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Step-by-step explanation:

3 0
3 years ago
Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for
KIM [24]

Answer:

a) The recurrence formula is P_n = \frac{109}{100}P_{n-1}.

b) The general formula for the population of Tacoma is

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write P_0 = 200 000. For the population in 2001 we will use P_1, for the population in 2002 we will use P_2, and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that P_0 is equal to P_1 plus 9% of the population of 2000. Notice that this can be written as

P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0.

In 2002, we will have the population of 2001, P_1, plus the 9% of P_1. This is

P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1.

So, it is not difficult to notice that the general recurrence is

P_n = \frac{109}{100}P_{n-1}.

b) In the previous formula we only need to substitute the expression for P_{n-1}:

P_{n-1} = \frac{109}{100}P_{n-2}.

Then,

P_n = \left(\frac{109}{100}\right)^2P_{n-2}.

Repeating the procedure for P_{n-3} we get

P_n = \left(\frac{109}{100}\right)^3P_{n-3}.

But we can do the same operation n times, so

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) Recall the notation we have used:

P_{0} for 2000, P_{1} for 2001, P_{2} for 2002, and so on. Then, 2016 is P_{16}. So, in order to obtain the approximate population of Tacoma in 2016 is

P_{16} = \left(\frac{109}{100}\right)^{16}P_{0} = (1.09)^{16}P_0 = 3.97\cdot 200000 \approx 794062

d) In this case we want to know when P_n>400000, which is equivalent to

(1.09)^{n}P_0>400000.

Substituting the value of P_0, we get

(1.09)^{n}200000>400000.

Simplifying the expression:

(1.09)^{n}>2.

So, we need to find the value of n such that the above inequality holds.

The easiest way to do this is take logarithm in both hands. Then,

n\ln(1.09)>\ln 2.

So, n>\frac{\ln 2}{\ln(1.09)} = 8.04323172693.

So, the population of Tacoma should exceed the 400 000 by the year 2009.

8 0
3 years ago
Read 2 more answers
1)
Mars2501 [29]

Answer:

$186.86

Step-by-step explanation:

<u>4 eggs cost:</u>

1 dollar per dozen (12 eggs), so by unitary method (ratios), we can find cost of 4 eggs. Shown below:

\frac{1}{12}=\frac{x}{4}\\12x=4\\x=0.33

So, 4 eggs cost $0.33 approx

<u>12 lb. flour cost:</u>

2.50 dollar per pound, so 12 pounds would simply cost:

2.5 * 12 = $30

<u>14 lb of sugar cost:</u>

4.50 dollar per pound means 14 pounds would cost:

4.5 * 14 = $63

<u>2 ready-made edible flowers cost:</u>

5 cents for each flower means 2 flowers would cost:

5 cent = 0.05 dollars

0.05 * 2 = $0.10

We add all up to find cost of 1 cake. Shown below:

Cost of 1 cake = $0.33 + $30 + $63 + $0.10 = $93.43

Cost of 2 cakes = $93.43 * 2 = $186.86

8 0
3 years ago
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