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marusya05 [52]
2 years ago
7

Solve the math problem

Mathematics
1 answer:
Colt1911 [192]2 years ago
6 0

Answer:I think its ether y-interspersed or equation

Step-by-step explanation:

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Good day!

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3 years ago
Once again plesse help me
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Number 10: 15
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4 0
3 years ago
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Suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
goblinko [34]

15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.

<h3>What is a permutation?</h3>

A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.

Now, 13P_{5}= 13!/(13-5)!

= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444

Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

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3 0
2 years ago
HOW TO DO THIS QUESTION ​
sdas [7]

Answer:

A ≈ 40.3 cm²

Step-by-step explanation:

The area of right Δ ACD is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here A = 50.5, b = CD and h = AC , then

\frac{1}{2} × 14 × AC = 50.5

7 AC = 50.5 ( divide both sides by 7 )

AC ≈ 7.214

The area of Δ ABC is calculated as

A = \frac{1}{2} × BC × AC × sin36°

  = 0.5 × 19 × 7.214 × sin36°

  ≈ 40.3 cm² ( to 3 sf )

3 0
2 years ago
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Simplify (3×22)÷6+(28-(4)2=
polet [3.4K]
(3*22)divide 6 + (28-(4)2=
31
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2 years ago
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