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Aleksandr-060686 [28]
2 years ago
15

Which type of network consists of multiple Windows computers that share information, but no computer on the network serves as an

authoritative source of user information
Computers and Technology
1 answer:
Alexxandr [17]2 years ago
7 0

The type of network that consists of multiple Windows computers that share information is peer-to-peer. In this network, the computer serves as an authoritative source of user information.

<h3>Peer-to-peer computer networks</h3>

A peer-to-peer (P2P) network can be defined as a type of network where the computer acts as a source of user information.

In P2P, a cluster of different computers are linked and they have the same permissions for processing data in the network.

This type of computer network (peer-to-peer computer network) has been created to serve and/or receive data.

Learn more about peer-to-peer computer networks here:

brainly.com/question/1172049

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Which specialized information system is used by passport agencies and border inspection agencies to check the names
katovenus [111]

Answer:

Consular Lookup and Support System

5 0
2 years ago
Which of the following decimal (base-10) values is equivalent to the binary (base-2) value 101001?
garik1379 [7]

Answer:

D. 41

Explanation:

101001 is in base 2.

To convert 101001 to base 10;

1*2^5+0*2^4+1*2^3+0*2^2+0*2^1+1*2^0

1*32+0*16+1*8+0*4+0*2+1*1

32+0+8+0+0+1

=41

8 0
3 years ago
We have a user Sally Smith who we want to grant the ability to launch applications and browse folders. But we do not want her to
igomit [66]

Answer:

LIST

Explanation:

NTFS is A proprietary journaling file system developed by Microsoft. It started with windows 3.1.

List Folder Contents: Is what Gives authorized user the permission to viewing and listing of files and sub-folders as well as executing of files inherited by folders only.

NTFS permissions applies to every file and folder stored on a volume formatted with the NTFS file system. By default, permissions are inherited from a root folder to the files and sub-folders beneath it, although this inheritance can be disabled.

List Folder Contents will allow you to display the folder's contents and to display the data, attributes, owner, and permissions for files within the folder.

The NTFS permission that applies to the Domain Users group that will allow Sally to do what he wants without allowing more access than necessary is LIST.

8 0
3 years ago
CHANGE POSITION OF SONG Enter song's current position: Enter new position for song: "Peg" moved to position 3 JAMZ PLAYLIST MENU
hichkok12 [17]

Answer:

Answers can be found below

Explanation:

port java.util.Scanner;

public class Playlist {

String title;

SongEntry head;

public Playlist(String title) {

this.title = title;

this.head = null;

}

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

System.out.println("Enter the playlist's title:");

String title = scanner.nextLine();

Playlist playList = new Playlist(title);

String option;

do {

option = playList.printMenu(scanner);

switch (option) {

case "a":

playList.addSong(scanner);

break;

case "d":

playList.removeSong(scanner);

break;

case "c":

playList.changePosition(scanner);

break;

case "s":

playList.outputSongByArtist(scanner);

break;

case "t":

playList.outpuTotalTime();

break;

case "o":

playList.outputFullPlayList();

break;

case "q":

System.out.println("QUIT");

break;

default:

System.out.println("please enter a valid option");

}

} while (!option.equals("q"));

}

public String printMenu(Scanner scanner) {

System.out.println(this.title + " PLAYLIST MENU");

System.out.println("a - Add song");

System.out.println("d - Remove song");

System.out.println("c - Change position of song");

System.out.println("s - Output songs by specific artist");

System.out.println("t - Output total time of playlist (in seconds)");

System.out.println("o - Output full playlist");

System.out.println("q - Quit");

System.out.println("Choose an option:");

String input = scanner.nextLine();

return input;

}

public void outputFullPlayList() {

if (head == null) {

System.out.println("Playlist is empty");

} else {

SongEntry tempNode = head;

while (tempNode != null) {

tempNode.printPlaylistSongs();

tempNode = tempNode.getNextNode();

}

}

}

public void addSong(Scanner scanner) {

System.out.println("ADD SONG");

System.out.println("Enter song's unique ID:");

String uniqueId = scanner.nextLine();

System.out.println("Enter song's name:");

String songName = scanner.nextLine();

System.out.println("Enter artist's name:");

String artistName = scanner.nextLine();

System.out.println("Enter song's length (in seconds):");

int length = Integer.parseInt(scanner.nextLine());

SongEntry song = new SongEntry(uniqueId, songName, artistName, length);

if (head == null) {

head = song;

} else {

SongEntry tempNode = head;

while (tempNode.getNextNode() != null) {

tempNode = tempNode.getNextNode();

}

tempNode.insertAfter(song);

}

}

public void removeSong(Scanner scanner) {

System.out.println("REMOVE SONG");

System.out.println("Enter song's unique ID:");

String uniqueId = scanner.nextLine();

SongEntry tempNode1 = head;

SongEntry tempNode2 = head;

while (tempNode1 != null) {

if (tempNode1.getUniqueID().equals(uniqueId)) {

if (tempNode1.getUniqueID().equals(head.getUniqueID())) {

6 0
3 years ago
; This program replaces the value in R0 with its absolute value. ; ; It does NOT modify any other registers! ; .ORIG x0200 START
olasank [31]

Using the knowledge in computational language in LC-3 Assembly it is possible to write a code that replaces the value in R0 with its absolute value

<h3>Writting the code </h3>

       .ORIG x0200

START

       AND R0, R0, #0  ; copy R0 to itself to set the condition codes based on R0;

                       ; i.e performing addition operation with Zero option to set the flags

       BRzp DONE       ; if R0 is NON-NEGATIVE, skip the negation (already correct);

                       ; Branch to DONE if number is poistive

       NOT R0, R0      ; R0 is negative, so negate it i.e taking 2's complement

       ADD R0, R0, #1  ; R0 = -R0 is performed successfully

DONE    BR START

       

       .END

See more about  LC-3 Assembly at brainly.com/question/12978370

#SPJ1

4 0
2 years ago
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