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a_sh-v [17]
2 years ago
13

Write an expression that would simplify to 14x - 21 * 30 pointsss

Mathematics
1 answer:
stich3 [128]2 years ago
5 0

Answer:

14x−21

There are no like terms.

Step-by-step explanation:

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Which of the following describe 8? Select all that apply.
pav-90 [236]

8 is a<u> Natural number, </u><u>Whole number, Integer and Real number</u>

<h3>What is an integer?</h3>

An integer is a number that cannot be expressed as fraction. They are known as whole numbers.

For natural numbers, they are value that starts from 1 and above. Since 8 is greater than 1, hence it is a natural number.

Real number includes both fractions and whole numbers, hence 8 is also a real number.

Based on the explanation, we can conclude that 8 is a<u> Natural number, </u><u>Whole number, Integer and Real number</u>

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8 0
2 years ago
Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
Rasek [7]

The area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners. It has one pair of opposite congruent angles and the diagonals of a kite are perpendicular.

We have a quadrilateral shown in the picture.

The diagonal divides the quadrilateral into two triangles

The area of the quadrilateral = area of the triangle ADC + area of the

                                                   triangle ADB

= (1/2)3.42×4.39 + (1/2)5.44×3.42

= 7.5069 + 9.3024

= 16.80 square units

Thus, the area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

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brainly.com/question/6321910

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7 0
2 years ago
What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFractio
aalyn [17]

Answer:

  StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction

Step-by-step explanation:

Apparently you want to simplify ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  1/a^b = a^-b

  (a^b)^c = a^(bc)

__

So the expression simplifies as ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}

9 0
3 years ago
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