Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16
<span>Triangles exist:
</span>3 acute angles<span>
2 acute angles, 1 right angle
</span><span>2 acute angles, 1 obtuse angle
</span>
Triangles DON'T exist for:
<span>1 acute angle, 1 right angle, 1 obtuse angle
</span><span>1 acute angle, 2 obtuse angles</span>
Answer:
B
Step-by-step explanation:
let f(x) = y and rearrange making x the subject
y = 
( multiply both sides by 7 to clear the fraction )
7y = x + 2 ( subtract 2 from both sides )
7y - 2 = x
Change y back into terms of x with x the inverse function, that is
p(x) = 7x - 2
There are many possible answers.
10:12
15:18
20:24
25:30
30:36
Answer:
sorry i dont understand it
Step-by-step explanation:
