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2 years ago

1. Circle ALL of the relations that represent functions.

Mathematics

2 answers:

REY [17]2 years ago

8 0

Only the first one is a function
functions can’t have more than one of the same x value

Mekhanik [1.2K]2 years ago

5 0

Answer:

The very first one is the only function.

Step-by-step explanation:

The first one is the only function because the input (or x) only has one output (or y)

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Step-by-step explanation:

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2 years ago

Which expressions are equivalent to when x0? Check all that apply.

Genrish500 [490]

We have that

$\frac{(x+4)}{3} / \frac{6}{x} = \frac{x*(x+4)}{3*6} \\ \\ = \frac{( x^{2} +4x)}{18}$

therefore

case a)
$\frac{(x+4)}{3} * \frac{x}{6}$
Is equivalent

case b)
$\frac{6}{x} * \frac{(x+4)}{3}$
Is not equivalent

case c)
$\frac{x}{6} * \frac{(x+4)}{3}$
Is equivalent

case d)
$\frac{(2 x^{2} +4x)}{6}$
Is not equivalent

case e)
$\frac{(2 x^{2} +4x)}{18}$
Is equivalent

Hence

the answer is

$\frac{(x+4)}{3} * \frac{x}{6}$

$\frac{x}{6} * \frac{(x+4)}{3}$

$\frac{(2 x^{2} +4x)}{18}$

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