The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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Answer:
A
Step-by-step explanation:
when x=2,g(x)=2
g(x)=(2)²/2=2
which is correct.
Answer:
4/9
Step-by-step explanation:
11/18-1/6
The first step is to get a common denominator, which is 18. We can multiply 1/6 by 3/3 to get the denominator to 18
11/18 - 1/6 *3/3
11/18 - 3/18
8/18
Now we can simplify the fraction by dividing the top and bottom by 2
4/9
