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Hoochie [10]
2 years ago
8

How do I solve this? 3(√x+1-5)=27

Mathematics
1 answer:
AnnyKZ [126]2 years ago
8 0

3(√x+1-5)=27

divide both sides by 3

√x+1-5= 27

add 5 to both sides

√x+1=27+5

√x+1=32

take square of both sides

x+1=32

subtract 1 from each sides

x=32-1

x=31

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