<span>SALES: 5x² + 2x – 80
</span>- COST: 5x² – x + 100
= ------------------
PROFIT: 0x²+3x-180
(+3x because we subtracted a negative (-x), which is called adding, similarly taking away 100 from negative 80 is -180.)
Checking:
5x² + 2x – 80
5(500)²+2(500)-80 = 1,250,920
5x² – x + 100
5(500)² – (500) + 100= 1,249,600
Profit = 1,250,920 - 1,249,600 = 1,320
0(500)²+3(500)-180 = 1,320 YAY! {:-)
Double Checking:
5x² + 2x – 80
5(5000)²+2(5000)-80 = 125,009,920
5x² – x + 100
5(5000)² – (5000) + 100= 124,995,100
Profit = 125,009,920 - 124,995,100 = 14,820
0(5000)²+3(5000)-180 = <span>14,820</span> YAY! {:-)
Answer:
x=14 y=6
Step-by-step explanation:
you put this in math, get the answer in history
Answer:
Step-by-step explanation:
Given that at the end of a math contest, each team must select two students to take part in the countdown round. As a math
team coach, you decide to randomly select two students from your team. You would prefer that the two students
selected consist of one girl and one boy.
If we have 6 girls and 6 boys, one girl can be selected in 6 ways and one boy also in 6 ways
No of ways = 36
Instead, If we have 5 girls and 5 boys, one girl can be selected in 5 ways and one boy also in 5 ways
No of ways = 25
First group is better as we have more choices to select the best one from each set of girl and a boy.
