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fredd [130]
3 years ago
7

Show how many groups of 0.5 are in 3.

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0

Answer:

The answer is 6 groups.

Step-by-step explanation:

0.5 is equal to one half.

What number is 3 half of?

3 is half of 6.

So the answer is 6.

Hope I helped ya.

<u><em>< Sarah ></em></u>

Alexxx [7]3 years ago
6 0

Answer:

6 times:)

Step-by-step explanation:

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Guys help me out on this one plizzz
evablogger [386]

<span>The term that you want is 5C2*p^2*q^3 representing 2 successes and 3 failures.  This term's value is</span>

<span>(5C2)(0.5^5) = 10*0.03125 = 0.3125 = P(2 successes in 5 trials) =31.3% </span>


5 0
4 years ago
Plz help as quick as possible!
kompoz [17]

average =65%

average = (60+70)/(100+100)*100

= 130/200*100

= 65%

6 0
3 years ago
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If (1)=3 and f(n)=f(n-1)-1 then find the value of f(6)
katrin [286]

Answer:

f(1) = 3

f(n) = f(n-1) - 1

Otherwise,

f(n) = f(1) - (n-1)

=> f(6) = 3 - 5 = -2

Hope this helps!

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8 0
3 years ago
Find the standard deviation of 21, 31, 26, 24, 28, 26
Vesnalui [34]

Given the dataset

x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}

We start by computing the average:

\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26

We compute the difference bewteen each element and the average:

x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}

We square those differences:

(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}

And take the average of those squared differences: we sum them

\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69

And we divide by the number of elements:

\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5

Finally, we take the square root of this quantity and we have the standard deviation:

\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39

8 0
3 years ago
What’s the correct answer for this question?
Maurinko [17]

Answer:

B

Step-by-step explanation:

I put the answer in an atachement

3 0
3 years ago
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