Option B:  is sufficient to prove that
 is sufficient to prove that  ll
 ll 
Explanation:
Given that ACD is a triangle.
The line EB intersects the sides AC and AD of the triangle.
The point E intersect the side AD and B intersect the side AC.
We need to prove that  ll
 ll 
Then, the side splitter theorem states that "If a line intersects two sides of a triangle and divides the sides proportionally, the line is parallel to the third side of the triangle".
From the side splitter theorem, the line EB intersects the two sides of the triangle AC and AD and divides the sides proportionally.
Thus, the proportion of the sides is given by

This proportionality shows that the line is parallel to the third side of the triangle.
Hence,  is sufficient to prove that
 is sufficient to prove that  ll
 ll 
Therefore, Option B is the correct answer.
 
        
             
        
        
        
Answer:
Let x be the unknown quantity of 50% silver.
Look at the silver concentrations...   This will be 0.5x of actual silver,
Added to 5% silver in 500g or 0.05(500)g of actual silver
Totaling to (500+x)g of 20% silver which will have 0.2(500+x)g of silver
 
Your equation is:
 
0.5x + 0.05(500) = 0.2(500+x)
 
Solve for x to find the grams of 50% silver used
 
Step-by-step explanation:
sana maka tulong po sorry po kung mali
 
        
             
        
        
        
Answer:
130, exterior, 8, 93, 87, interior 
Step-by-step explanation:
 
        
             
        
        
        
Given: 
t = 1/2 √v
v = speed of object meters per second
t = 3 seconds
3 = 1/2 √v
3 * 2 = √v
6 = √v
6² = √v²
36 meters = v
v = 36 meters per second
        
             
        
        
        
Answer:
The distance is:
d = 10.0 units (Rounded to the nearest the Tenths Place) 
Step-by-step explanation:
Given the points
The distance 'd' between (3,4) and (4,-6)


substituting the points values
    
    
    
    
     units (Rounded to the nearest the Tenths Place)
  units (Rounded to the nearest the Tenths Place) 
Thus, the distance is:
d = 10.0 units (Rounded to the nearest the Tenths Place)