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coldgirl [10]
3 years ago
14

The area of the closet floor is 18 feet. If Saroya buys 32 tiles will she have enough to cover the floor?

Mathematics
1 answer:
kvasek [131]3 years ago
4 0
No shel will not have enough tile.  If you don't know the dimensions of the actual tile how will you solve.  If you have a closet 18 square feet it could be 9 ' x 2 ' = 18 square feet. If the tiles were 12" x 6" you would need 36 tiles.  If the closet was 6' x 3' = 18 square feet you could have the tiles 12" x 6" = 36 tiles.  So you need to know the dimensions of the tile.
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Rider ordered 2 hot dogs and 5 hush puppies. His total was $4.70. Write an equation in standard form for this relation, using x
yaroslaw [1]

Answer:

2x + 5y = 4.70

Step-by-step explanation:

Rider ordered 2 hot dogs and 5 hush puppies. His total was $4.70. Write an equation in standard form for this relation, using

From the above question, note that

x = cost of a hot dog

y = cost of a hush puppy.

Our Standard Equation is given as

2 × x + 5 × y= $4.70

2x + 5y = 4.70

3 0
3 years ago
Which shows the correct simplification of product of powers?
Brums [2.3K]
The power symbols are missing.

I can infere that the product intended to simplify is (7^8) * (7^-4)., because that permits you to use the rule of the product of powers with the same base.

That rule is that the product of two powers with the same base is the base raised to the sum of the powers is:

(A^m) * (A^n) = A^ (m+n)

=>(7^8) * (7^-4) =  7^ [8 + (- 4) ] = 7^ [8 - 4] = 7^4, which is the option 3 if the powers are placed correctly.
5 1
4 years ago
Read 2 more answers
Determine the zeros of f(x)=x^3+7x^2+10x-6
igor_vitrenko [27]
Hello,
x^3+7x^2+10x-6=x^3+3x^2+4x^2+12x-2x-6
=x²(x+3)+4x(x+3)-2(x+3)
=(x+3)(x²+4x-2)
=(x+3)(x+2-√7)(x+2+√7)

zeroes={-3,-2+√7,-2-√7}

4 0
3 years ago
Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3
Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

f\left(x\right)=\sqrt{x^3-16x}

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

x^3-16x\ge 0

as x³ - 16x ≥ 0

\left(x+4\right)\left(x-4\right)\ge \:0

Thus, identifying the intervals:

-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4

Thus,

The domain of the function f(x) is:

x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}

And the Least Value of the domain is -4.

3 0
3 years ago
Can someone give me the answers for these?
Alinara [238K]
I think the first one is ( C :3 ) and the other one is B 2
5 0
3 years ago
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