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borishaifa [10]

2 years ago

7

Imperial telephone has a long distance calling plan that has a monthly fee of $10 and a charge of $0.03 per minute. Mayflower Co

mmunications has a monthly fee of $6 and a fee of $0.04 per minute. For how many minutes is Imperial Telephone the cheaper plan?
I don't understand the equations and how to do this lol help

2 answers:

dezoksy [38]2 years ago

6 0

Answer:

Mayflower Communications is the cheaper plan

Step-by-step explanation:

sorry this is all i could come up with

Shalnov [3]2 years ago

3 0

Any amount of the greater than four hundred minutes

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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three op

klasskru [66]

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The standard form of a quadratic equation is:

y = ax² + bx + c

The graph of a quadratic equation is a parabola.

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

4 0

2 years ago

Please help veryyy urgent due today!!!!!!

Musya8 [376]

42 is the answer....

4 0

3 years ago

Hello and it would be very helpful if you know these answers!

Wittaler [7]

Answer:

1) 15-4x

2) 3x+2

Step-by-step explanation:

1) product of x and 4 is 4x then subtract that from 15

2) use x as your age in this situation so your age times 3 is 3x and since he's 2 years older than that u add 2 more

5 0

3 years ago

Use the figure from the example to find the length GH. Assume △DEF ≅ △GHJ.

grandymaker [24]

The two triangles are congruent, so corresponding parts of the two triangles are congruent.
GH is corresponding to DE, so GH=DE=17

8 0

3 years ago