Answer:
That would be the fraction exactly between 2/7 and 3/7
which would be 2.5 / 7 or 5 / 14
Step-by-step explanation:
Answer:
---- in dollars
---- in cents
5 dollars 94 cents
Step-by-step explanation:
Given
Pears
per pound
Grapes
per pound
Required
Determine the amount paid for the fruit in dollar and cents
First, we need to calculate the amount paid for each fruit.
This is calculated by multiplying the amount per pound by the number of pounds bought.
For Pears:
Convert fraction to decimal
For Grapes
Convert fraction to decimal
Next, we add both amounts together to get the total amount spent in dollars.
Multiply by 100 to convert this amount to cents
And it can be represented as dollars and cents as:
5 dollars 94 cents
Answer:
how much was originally?
Step-by-step explanation:
Answer:
a. 25.98i - 15j mi/h
b. 1.71i + 4.7j mi/h
c. 27.69i -10.3j mi/h
Step-by-step explanation:
a. Identify the ship's vector
Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h
Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h
b. Identify the water current's vector
Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h
Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h
c. Identify the vector representing the ship's actual motion.
The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.
V = v + v'
= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h
= (25.98i + 1.71i + 4.7j - 15j )mi/h
= 27.68i -10.3j mi/h
Cost of fuel = 30% of $400 000 = 30/100 x 400000 = $120 000
Fuel amount = $120 000/$1.5 = 80 000 liters
new cost of fuel = 80000 x $1.6 = $144 000
increase in cost = 144000 - 120000 = $24000
So the increase in petrol price increases the operating cost by $24000
