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Mamont248 [21]
2 years ago
14

Nonlmf'adnklsek;lk;kjfjklljkfsjklfsk

Mathematics
1 answer:
UNO [17]2 years ago
6 0

Answer:

lol brainliest pls :D

Step-by-step explanation:

©️

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Im in Algebra What is <br>2r-6+5r=3-r+7
worty [1.4K]
2r-6+5r=3-r+7

7r-6=10-r

7r+r=10+6

8r=16

r=16/8

r=2
7 0
2 years ago
8/5 of 3/7 is.......
EastWind [94]

Answer:

8/5×3/7=  

8 × 3

5 × 7

=  24/35

Step-by-step explanation:

24/35

7 0
2 years ago
PLEASE HELP! i have by the end of the day to turn this in. PLEASE DONT GUESS
ivann1987 [24]

Answer: See step by step

Step-by-step explanation: Angle 2 and 3 are vertical angles since they both share a vertex and has cross intersecting lines. Angle  6 and 7 are supplementary angles because they forma linear pair.

7 0
3 years ago
Read 2 more answers
In a major hurry to finish this I was stuck doin other homework last year please help me finish this
Irina-Kira [14]

2 = m ≤ −9

3 = p ≥ 5

4  =  x < -10

5 = b < -10

6 = n < 5

7 = n < 6

8 = r ≤ 4

9 = x ≥ 9

10 = p ≤ 0

11 = x < 1

12 = a > 24

6 0
3 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0
2 years ago
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