This is the concept of geometry, given that AB=AC, it means that the tirangle is isosceles, thus to get the value of AB and AC we proceed as follows;
thus using the cosine rule:
c^2=a^2+b^2-2abcosC
suppose\AB=AC=x
thus;
8^2=x^2+x^2-2*x*xcos15
64=2x^2-2x^2cos15
64=2x^2-1.9x^2
64=0.1x^2
x^2=640
x=sqrt640
x=25.3
hence;
AC=AB=25.3
Well m is 2 and b is 3
Using the equation y=Mx+B
Factor : x^2+3x-10
Answer = (x - 2)(x + 5)
Explanation:
Y = x^2 + 3x - 10.
Find 2 numbers knowing sum (3) and product (-10).
Factor pairs of (-10) -> (-1, 10)(-2, 5). This sum is 3 = b. The 2 numbers are: -2 and 5.
y = (x - 2)(x + 5).
