Answer:
a) 20<h≤30.
b) 26.17 hrs
Step-by-step explanation:
The missing table is shown in attachment.
Part a)
We need to find the class interval that contains the median.
The total frequency is

The median class corresponds to half

That is the 15th value.
We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.
2+8+9=19
This corresponds to the class interval 20<h≤30.
Adding from the bottom also gives the same result.
Therefore the median class is 20<h≤30.
b) Since this is a grouped data we use the midpoint to represent the class.
The median is given by :




Answer:
no angle c is not supplementary
Step-by-step explanation:
Angle A and angle B are supplementary
A+B=180° Equation 1
The measure of angle B is equal to four times the complement of angle A
The complement of angle A=90°-A
B=4(90°-A)
B=360°-4A
Substitute the value of B in equation 1
A+360°-4A=180°
-3A=-180°
A=60°
The measure of angle A=60°
B=360°-4A=360°-4(60°)=120°
The measure of angle B=120°
Answer:
x = 3
Step-by-step explanation:
..........................
True y=2x+1 and y-3x=4 it would be the same way because you can solve for x and you can solve for y