B or d are most likely it I could be wrong if I am, I am so sorry:)
Answer:
a) the probability is P(G∩C) =0.0035 (0.35%)
b) the probability is P(C) =0.008 (0.8%)
c) the probability is P(G/C) = 0.4375 (43.75%)
Step-by-step explanation:
defining the event G= the customer is a good risk , C= the customer fills a claim then using the theorem of Bayes for conditional probability
a) P(G∩C) = P(G)*P(C/G)
where
P(G∩C) = probability that the customer is a good risk and has filed a claim
P(C/G) = probability to fill a claim given that the customer is a good risk
replacing values
P(G∩C) = P(G)*P(C/G) = 0.70 * 0.005 = 0.0035 (0.35%)
b) for P(C)
P(C) = probability that the customer is a good risk * probability to fill a claim given that the customer is a good risk + probability that the customer is a medium risk * probability to fill a claim given that the customer is a medium risk +probability that the customer is a low risk * probability to fill a claim given that the customer is a low risk = 0.70 * 0.005 + 0.2* 0.01 + 0.1 * 0.025
= 0.008 (0.8%)
therefore
P(C) =0.008 (0.8%)
c) using the theorem of Bayes:
P(G/C) = P(G∩C) / P(C)
P(C/G) = probability that the customer is a good risk given that the customer has filled a claim
replacing values
P(G/C) = P(G∩C) / P(C) = 0.0035 /0.008 = 0.4375 (43.75%)
Answer:
Step-by-step explanation:
Given that sample size = n=45
mu = 64 and sigma =14
a) Sample mean will follow a normal distribution irrespective of the original distributions provided
i) samples are randomly drawn
ii) samples represent the population
iii) Sample size is sufficiently large
b) Here we have sample std dev= 
c) 
