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2 years ago

12

Please anyone solve this for me..No spam.

1 answer:

Tamiku [17]2 years ago

3 0

Answer:

3096

Step-by-step explanation:

<u>Given:</u>

$3x-\frac{1}{4y}=24$

<u>Rewrite it as:</u>

$3x=\frac{1}{4y}+24$
$x=\frac{1}{12y}+8$

<u>Simplify the expression:</u>

$8x(6x - \frac{1}{y} ) + \frac{1}{12y^2} (4 - 3y + 36xy^2) =$
$8(\frac{1}{12y}+8)(6(\frac{1}{12y}+8) - \frac{1}{y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 3x =$
$8(\frac{1}{12y}+8)(48- \frac{1}{2y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 24 + \frac{1}{4y} =$
$8(\frac{4}{y}+8*48- \frac{1}{24y^2} -\frac{4}{y} ) + \frac{1}{3y^2} + 24 =$
$8(384-\frac{1}{24y^2}) + \frac{1}{3y^2} + 24 =$
$8*384-\frac{1}{3y^2} + \frac{1}{3y^2} + 24 =$
$3072+24=$
$3096$

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