Question

Please anyone solve this for me..No spam.​

Answer 1

Answer:

• 3096

Step-by-step explanation:

Given:

• $3x-\frac{1}{4y}=24$

Rewrite it as:

• $3x=\frac{1}{4y}+24$
• $x=\frac{1}{12y}+8$

Simplify the expression:

• $8x(6x - \frac{1}{y} ) + \frac{1}{12y^2} (4 - 3y + 36xy^2) =$
• $8(\frac{1}{12y}+8)(6(\frac{1}{12y}+8) - \frac{1}{y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 3x =$
• $8(\frac{1}{12y}+8)(48- \frac{1}{2y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 24 + \frac{1}{4y} =$
• $8(\frac{4}{y}+8*48- \frac{1}{24y^2} -\frac{4}{y} ) + \frac{1}{3y^2} + 24 =$
• $8(384-\frac{1}{24y^2}) + \frac{1}{3y^2} + 24 =$
• $8*384-\frac{1}{3y^2} + \frac{1}{3y^2} + 24 =$
• $3072+24=$
• $3096$