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Valentin [98]
3 years ago
10

What is the answer to 5/12 - 3/20?

Mathematics
1 answer:
svetlana [45]3 years ago
7 0
0.116 that is the answer
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The figure below shows square ABCD inscribed on square PQRM on a coordinate plane. Which of the following expressions represents
klasskru [66]

Answer:

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Step-by-step explanation:

55555555

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2 years ago
Whats the mean absolute deviation of 2 2 2 2 2 2 2 2
saveliy_v [14]

Answer:

mad is 0

Step-by-step explanation:

what type of question is this? no offense

6 0
2 years ago
Multiply the following and write your answer In scientific notation.. 3.62 × 10^-5 · 9,400.
svet-max [94.6K]

Answer:

3.4028 x 10^-1

Step-by-step explanation:

First you make the 9400 into scientific notation:

9.4x10^3

Then you combine like terms

(3.62x9.4)(10^-5x10^3)

Finally you simplify

34.028x10^-2

3.4028x10^-1


6 0
3 years ago
18x = ~36?
FromTheMoon [43]

Answer:

from the picture the answer is D.

Step-by-step explanation:

2 \ti4mes \f7rac{?}{?}

to find x subtract 18x from 4x which will give you -14x=-36

divide both sides by -14

4 0
3 years ago
A simple random sample with n = 58 provided a sample mean of 24.5 and a sample standard deviation of 4.4. (Round your answers to
nasty-shy [4]

Answer: (23.53, 25.47)

Step-by-step explanation:

The confidence interval for population mean(when population standard deviation is unknown) is given by :-

\overline{x} \pm\ t^*\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n = sample size.

s = sample standard deviation.

t* = Critical value.

Given : \overline{x}=24.5

s= 4.4

Confidence level = 90% =0.090

Significance level = \alpha=1-0.90=0.10

Sample size : n= 58

Degree of freedom : df= n-1= 57

Using t-distribution table , the critical value :

t_{\alpha/2,\ df}= t_{0.05,\ 57}=1.6720

Then, the confidence interval will be :-

24.5 \pm\ (1.6720)\dfrac{4.4}{\sqrt{58}}

24.5 \pm\ (1.6720)\dfrac{4.4}{7.61577310586}

24.5 \pm\ 0.965995165263\approx24.5\pm0.97\\\\=(24.5-0.97,\ 24.5+0.97)\\\\=(23.53,\ 25.47)

Hence, a 90% confidence interval for the population mean = (23.53, 25.47)

6 0
3 years ago
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