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Ainat [17]
3 years ago
7

Find the area to this figure

Mathematics
1 answer:
12345 [234]3 years ago
7 0

I think the answer is 62 cm2

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Sam is serving ice cream with the birthday cake at his party. he has purchased 19 1/2 pints of ice cream . she will serve 3/4 of
Fittoniya [83]
First let's put it into decimals. 19.5 pints of ice cream, everyone gets .75 pints.

19.5 divided by .75 is 26 with no remainder

She can serve 26 guests and will not have any leftover.
3 0
3 years ago
Read 2 more answers
the sum of the first 20 terms of an A.P is identical to the sum of the first 22 term.If the common difference is -2; find the fi
Goryan [66]

Answer:

First term a = 41

Step-by-step explanation:

Arithmetic Progression:

Common differences d = -2

S_{n}=\frac{n}{2}(2a+[n-1]d)\\\\S_{20}=\frac{20}{2}(2a+19*[-2])\\\\

  = 10*(2a - 38)

 = 10*2a - 10*38

=20a - 380

S_{22}=\frac{22}{2}(2a+21*[-2])\\\\

= 11 (2a -42)

=11*2a - 11*42

= 22a - 462

S_{22}=S_{20}\\\\

22a - 462 = 20a - 380

22a = 20a - 380 + 462

22a = 20a + 82

22a - 20a = 82

2a = 82

a = 82/2

a = 41

First term a = 41

7 0
3 years ago
Help please!!!!!!!!!!!!!!!!!!!!!!!!!!!
tester [92]

Answer:

B, E and F

Step-by-step explanation:

(1,2) is a solution to the system of equations.

8 0
4 years ago
A plane flying at a certain altitude is observed from two points that are 2.2 meters apart. The angles of elevation made by the
lana [24]
tan(72)= \frac{y}{x}  ; tan(55)= \frac{y}{2.2 + x}
y=xtan(72);y=(2.2+x)tan(55)
So we are to merge the two equations into one, since both of the equations are equal to y. a = b, b = c therefore, a = c.
xtan(72)=2.2tan(55)+xtan(55)
We are to isolate x.
x[tan(72)-tan(55)]=2.2tan(55)
x=\frac{2.2tan(55)}{tan(72)-tan(55)}
The value of x is approximately, 1.9047m
Then, substitute the value of x from y=xtan(72)
y=1.9047tan(72)
y = 5.862m
Round up, then the answer would be D.

7 0
3 years ago
Whats 11+​(-​3)-1/8 j-3/8 j+7 ?<br><br> Thanks in advance!
Anuta_ua [19.1K]

Answer:

Your answer is

=-\frac{j}{2}+15

Step-by-step explanation:

11+​(-​3)-1/8 j-3/8 j+7

=11+\left(-3\right)-\frac{1}{8}j-\frac{3}{8}j+7\\

=11-3-\frac{1}{8}j-\frac{3}{8}j+7

add the similar objects

=11-3-\frac{1}{2}j+7

=\frac{1}{2}j=\frac{j}{2}

=11-3-\frac{j}{2}+7

=-\frac{j}{2}+15

6 0
3 years ago
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