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2 years ago

What is the solution to the inequality -13x+6<14-5x

Mathematics

1 answer:

kvv77 [185]2 years ago

7 0

Answer:

x > -1

Step-by-step explanation:

$-13x+6$

$-13x+5x$

$-8x$

$\frac{-8x}{-8} >\frac{8}{-8}$

$x>-1$

* Remember that,

if you have a negative sign (-) infront of the x you have to change the direction of the inequality sign.

Hope this helps you .

Let me know if you have any other questions :-)

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Can someone please answer 8|x+2|-6=5|x+2|+3

Anettt [7]

Step-by-step explanation:

8|x+2|-6=5|x+2|+3

|8x+16|-6=|5x+10|+3

I've been thinking... Is that | or (? Are you sure it's |?

Oh well, I'm continuing...

8x+16-6=5x+10+3

8x+10=5x+13

3x=3

x=1

4 0

3 years ago

A. After Lou poured 2 liters of water into a large jug, the jug

Finger [1]

Answer:

8 liters

Step-by-step explanation:

If the sum of 2 + x = 10,

then you subtract 10 - 2 = x,

to get x = 8

4 0

2 years ago

Read 2 more answers

Polygon ABCD is a rectangle what is the area

Andre45 [30]

Solution:

As, You have Written Polygon ABCD is a rectangle.

It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).

Join any of the diagonal of Rectangle either AC or B D.

In Right Δ ABC , Right angled at B

${\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AB \times BC$ ---(1)

In Right Δ ADC , Right angled at D

${\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AD \times DC$ ---(2)

Adding (1) and (2) that is LHS to LHS and RHS to RHS

Ar( Δ ABC) +Ar( Δ ADC) $=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC$