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Over [174]
3 years ago
13

7. The graphed lines represent the linear equations y=2x+1 and y = 2x-4.

Mathematics
1 answer:
Mariana [72]3 years ago
4 0

Answer:

0

Step-by-step explanation:

If we set up an equation, we get:

2x+1 = 2x-4

We subtract 2x from both sides and get:

1 = -4

That is FALSE, so that means there are NO solutions

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Write z=1-3i in exponential form ​
Sladkaya [172]

Answer:

z=re ^iθ =2e ^i 3/π

​

Step-by-step explanation:

hope this helps

7 0
3 years ago
A college basketball court is 94 feet long and 50 feet wide. What is the diagonal length of the court?
g100num [7]
Drawing a diagonal will create two right triangles. So you can use a^2+ b2 =c^2
So approximately 106.47 feet or the square root of 11336
4 0
3 years ago
) a, p and d are n×n matrices. check the true statements below:
BigorU [14]
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose \mathbf P is the matrix of the eigenvectors of \mathbf A, and \mathbf D is the diagonal matrix of the eigenvalues of \mathbf A:


\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}

\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}

Then

\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}

In other words, the columns of \mathbf{AP} are \mathbf{Av}_i, which are identically \lambda_i\mathbf v_i, and these are the columns of \mathbf{PD}.

c. False. A counterexample is the matrix

\begin{bmatrix}1&1\\0&1\end{bmatrix}

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

\begin{bmatrix}0&1\\0&0\end{bmatrix}

with eigenvalue \lambda=0 and eigenvector \begin{bmatrix}k&0\end{bmatrix}^\top, where k\in\mathbb R. But the matrix can't be diagonalized.
7 0
3 years ago
To borrow​ money, you pawn your guitar. Based on the value of the​ guitar, the pawnbroker loans you ​$
Nonamiya [84]
\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$1472\\
P=\textit{original amount}\to& \$1080\\
r=rate\\
t=years\to &\frac{1}{12}
\end{cases}
\\\\\\
1472=1080\left(1+r\cdot \frac{1}{12}\right)

notice, it was pawned for only 1 month, so the "yearly" rate is for 1 month, which is 1/12 of the year, since a year has 12 moths

you'll get a rate in decimal terms, to get the % amount, just multiply it times 100
6 0
3 years ago
Where can the perpendicular bisectors of the sides of a right triangle intersect? I. inside the triangle II. on the triangle III
Slav-nsk [51]
Im pretty sure its either B. or C.
7 0
3 years ago
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