The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for 
is 9.
Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and 
for 8<t<11.
A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.
B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.
C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.
D) In this we have to find the function at when m belongs to 
the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.
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Answer:
25/30 and 28/30
Step-by-step explanation:
1. To find the least common denominator, you need to find the least common multiple of the two denominators which are 6 and 15. Prime factorization of these numbers gives:
6 = 2 x 3
15 = 5 x 3
A number that would evenly divide both 6 and 15 must contain 2 x 3 x 5 which is 30.
Thus 30 is the least common denominator.
2. Now we need to somehow change both fractions to make them have a denominator of 30. To do this we can multiply by fractions with same numerator and denominator since that would be like multiplying by 1.
So, 5/6 x 5/5 = 25/30
And 14/15 x 2/2 = 28/30
Answer:
C' (- 3, 2 )
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
C (3, 2 ) → C' (- 3, 2 )
Answer:
1, see the picture below, I used a calculator!
I hope this helps!!
