I'm not sure, but it's probably that Mary bakes faster than Sarah?
Answer:
5x + 2x.....combine like terms..... = 7x
5x + 2x....subbing in 1 7x - 1....subbing in 1
5(1) + 2(1) = 5 + 2 = 7 7(1) - 1 = 7 - 1 = 6
5x + 2x...subbing in 2 7x - 1...subbing in 2
5(2) + 2(2) = 10 + 4 = 14 7(2) - 1 = 14 - 1 = 13
5x + 2x...subbing in 3 7x - 1...subbing in 3
5(3) + 2(3) = 15 + 6 = 21 7(3) - 1 = 21 - 1 = 20
5x + 2x...subbing in 4 7x - 1....subbing in 4
5(4) + 2(4) = 20 + 8 = 28 7(4) - 1 = 28 - 1 = 27
5x + 2x...subbing in 5 7x - 1...subbing in 5
5(5) + 2(5) = 25 + 10 = 35 7(5) - 1 = 35 - 1 = 34
5x + 2x result values are 1 more then 7x - 1 result values
there are no values that will make the 2 expressions equal....
because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one
Step-by-step explanation:
Answer: Statements 1 and 2 shows that the coach blowing the whistle happened first.
Step-by-step explanation: The coach blowing the whistle as the first event can be seen only from statements 1 and 2 only.
From statement 1, "the referee blew the whistle" was followed by "the team ran onto the field."
From statement 2, "before the team ran onto the field" shows clearly that one event took place "BEFORE" the one being reported and the one that occurred before this one was "the referee blew the whistle."
Statement 3 which is "the referee blew the whistle, BUT..." indicates that the whistle was meant to prevent the team from from running onto the field. So if the referee blew the whistle, but the team ran onto the field, it means the whistle blowing was not supposed to make them run onto the field.
Statement 4, which states that "the referee blew the whistle BECAUSE the team ran onto the field" indicates that, the reason for blowing the whistle was because the team ran onto the field which clearly shows that the team ran onto the field first before the referee blew the whistle.
Statement 5, "WHILE the team ran onto the field..." clearly shows that both events took place at the same moment, and so the referee blowing the whistle could not have occurred first.
F=P(1/2)^(t/h)
F=future amount
P=present amount
t=time elapsed
h=legnth of half life
P=96
t=2
h=1
F=96(1/2)^(2/1)
F=96(1/2)^2
F=96(1/4)
F=96/4
F=24 grams
grow by 35%
compound interest
F=P(1+rate)^time
F=95000(1+0.35)^10
F=95000(1.35)^10
F=95000(20.106555868618)
F=1910122.9075187
All the numbers in this range can be written as

with

and

. Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number

shows up

times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.