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Oliga [24]
3 years ago
14

Please help me with this math problem!! NO LINKS PLEASE!! Will mark brainliest if correct! :)

Mathematics
1 answer:
andrezito [222]3 years ago
4 0
Line AC=21cm
line AB=20cm

substitute values into the pythagorean theorem to find the hypotenuse
(a^2 + b^2 = c^2):

(21)^2 + (20)^2 = c^2
441 + 400 = c^2
841 = c^2
29=c

so, line BC = 29cm

hope this was helpful :)
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The four-member math team at Pecanridge Middle School is chosen from the math club, which has three girls and five boys. How man
cestrela7 [59]

Answer:

Total\ Selection = 30\ ways

Step-by-step explanation:

Given

Girls = 3

Boys = 5

Required

How many ways can 2 boys and girls be chosen?

The keyword in the question is chosen;

This implies combination and will be calculated as thus;

Selection =\  ^nC_r = \frac{n!}{(n-r)!r!}

For Boys;

n = 5 and r = 2

Selection =\  ^5C_2

Selection = \frac{5!}{(5-2)!2!}

Selection = \frac{5!}{3!2!}

Selection = \frac{5 * 4 * 3!}{3!*2 * 1}

Selection = \frac{20}{2}

Selection = 10

For Girls;

n = 3 and r = 2

Selection =\  ^3C_2

Selection = \frac{3!}{(3-2)!2!}

Selection = \frac{3!}{1!2!}

Selection = \frac{3 * 2!}{1 *2!}

Selection = \frac{3}{1}

Selection = 3

Total Selection is calculated as thus;

Total\ Selection = Boys\ Selection * Girls\ Selection

Total\ Selection = 10 * 3

Total\ Selection = 30\ ways

5 0
4 years ago
You have 40 red apples and 39 green apples in a bag. You are not allowed to look inside the bag. How many apples you have to tak
Ray Of Light [21]

Answer:

3.

Step-by-step explanation:

There is no factor of luck here. If you choose three, two must be of the same colour.

5 0
3 years ago
The digit in the ones place is one. The digits in the tens place is double the ones. The debit in the hundreds place is double t
mixas84 [53]
What we know: ones = 1, tens -->1x2 = 2, hundreds --> 2x2= 4, thousands --> 4x2 = 8. 

8421
4 0
4 years ago
The police uses a speed gun to monitor one part of the highway. During one hour, 6 out of 25 cars were traveling above the speed
Oksanka [162]

24% of the cars were travelling above the speed limit.

Step-by-step explanation:

Given,

Total cars monitored = 25

Cars traveling above the speed limit = 6

Percent of cars traveling above speed limit = \frac{Cars\ travelling\ above\ speed\ limit}{Total\ cars\ monitored}*100

Percent of cars = \frac{6}{25}*100\\

Percent\ of\ cars=\frac{600}{25}\\Percent\ of\ cars=24\%

24% of the cars were travelling above the speed limit.

Keywords: percentage, division

Learn more about division at:

  • brainly.com/question/9532142
  • brainly.com/question/9590016

#LearnwithBrainly

7 0
4 years ago
Seven twelfth minus two fourths
pochemuha
One twelths 1/12 try to find a commen denominator or use a caculator 
3 0
3 years ago
Read 2 more answers
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