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alina1380 [7]
3 years ago
15

ILL GIVE BRAILIEST JUST ANSWER IT RIGHT

Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0
<span>Cold fronts are marked on weather maps with the symbol of a blue line of triangles/spikes (pips) pointing in the direction of travel, and are placed at the leading edge of the cooler air mass. That cold/dense air wedges its way under the warm air out ahead of it.
</span><span>Warm fronts are marked on weather maps with a red line of half circles pointing in the direction of travel and mark the edge of an advancing warm air mass; a flow of warmer air that overtakes and replaces colder air. They are usually found on the east side of low-pressure storm systems. Since the cold air is denser than the warm air, the cold air hugs the ground. The lighter warm air slides up and over the cold air (called “overrunning”) and lacks any direct push on the cold air. Thus, the cold air is slow to retreat in the rapid advance of the warm air. This slowness of the cold air to retreat produces an atmospheric slope that is more gradual than the sharper slope that accompanies a cold front.
</span><span>Stationary fronts are depicted by alternating red half-circles and blue spikes (pips) pointing in opposite directions, indicating no significant movement. When neither air mass is replacing the other, the frontal boundary becomes more-or-less stationary; the opposing forces exerted by adjacent air masses of different densities are such that the frontal surface between them shows little or no movement (sometimes also referred to as a “quasi-stationary” front). In such cases, the surface winds tend to blow parallel to the frontal zone. The resultant weather is usually low cloud cover and long duration precipitation, and not much in the way of wind.
</span>
i gave yu a little bit more info but read the stationary one 

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308 students went on a field trip. Ten buses were filled and 8 students traveled in cars. How many students were in each bus ?
jolli1 [7]

Answer:

30 students per bus

Step-by-step explanation:

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4 years ago
SPIDER ~ HNYCMB<br> Find NY, YC, CM, AND MB.
zzz [600]

Answer:

HN = 66, NY = 27, YC = 30, CM = 27, MB = 42,

Step-by-step explanation:

When comparing the two shapes, SPIDER is 0.75 times larger than HNYCMB. Besides this small detail they are the same shape. We can determine this by identifying which sides are most similar and dividing them, if SP "=" HN, then to find the rate at which figure HNYCMB shrank is to divide SP by HN. 66/88 is 0.75. By multipying the sides of figure SPIDER by 0.75, we get our answers.

HN ~ SP, 66 = 88 * 0.75, HN = 66

NY ~ SR, 27 = 36 * 0.75, NY = 27

YC ~ RE, 30 = 40 *  0.75, YC = 30

CM ~ ED, 27 = 36 * 0.75, CM = 27

MB ~ DI, 42 = 56 * 0.75, MB = 42

BH ~ PI, BH = ? Try this one by yourself for understanding

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