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balu736 [363]
2 years ago
8

Hundredths 6.1=_____hundreds

Mathematics
1 answer:
svlad2 [7]2 years ago
3 0

Answer:

I think that the answer is 0.061

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Factor:<br> x2 + 9x - 36
blagie [28]

Answer:

11x-36

for your answers

7 0
3 years ago
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Can someone please explain how to find this answer? thanks
N76 [4]
I would start with the standard form equation of the parallel line.
.. 5x -2y = 5(-2) -2(3) = -16
Then solve for y.
.. 2y = 5x +16 . . . add 2y+16; then divide by 2 for the next equation
.. y = (5/2)x +8 . . . . . . . corresponds to selection (B)
6 0
3 years ago
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What is the answer and how to do this?​
zhenek [66]

Answer:

<u>a</u>

Step-by-step explanation:

Given :

⇒ P (Sumit) = 1/2

⇒ P (Sujan) = 1/3

⇒ P (Rakesh) = 1/a

⇒ P (total) = 3/4

============================================================

Solving :

⇒ 1/2 × 1/3 × 1/a = 3/4

⇒ 1/6 × 1/a = 3/4

⇒ 2/12 × 1/a = 9/12

⇒ a = <u>9/2</u>

6 0
1 year ago
On a 8.5 x 11 inches (or larger) paper, create a carnival game (for example it could be: throwing a dart at a target, ball throu
Keith_Richards [23]

The probability of winning the game is 0.065

<h3>The description of the game</h3>

The game involves throwing two darts at two targets.

To win the game, the darts must hit anywhere in the following shapes

  • Rectangle: 5 by 4 inches
  • Circle: Radius, r = 3 inches

<h3>The probability of winning</h3>

The area of the paper is:

Area = 8.5 inches * 11 inches

Area = 93.5 square inches

The area of the rectangle on the paper is:

Area = 5 inches * 4 inches

Area = 20 square inches

The area of the circle on the paper is:

Area = π * (3 inches)²

Area = 28.3 square inches

The probability of landing on both shapes is

P(Both) = 20/93.5 * 28.3/93.5

Evaluate

P(Both) = 0.065

Hence, the probability of winning the game is 0.065

Read more about probability at:

brainly.com/question/24756209

#SPJ1

7 0
1 year ago
How do you factor 125-x^3?
xz_007 [3.2K]

Step-by-step explanation:

We have

125 - x {}^{3}

First, 125 is a perfect cube because

5 \times 5 \times 5 = 125

and

x^3 is a perfect cube because

x \times  x \times x = x {}^{3}

so we can use the difference of cubes identity

( {x}^{3}  -  {y}^{3} ) = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

64 - 27

we know that

64 - 27 = 37

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

(4 - 3)( {4}^{2}  + 4(3) + 3 {}^{2} )

1(16 + 12 + 9) = 1(37) = 37

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

(5 - x)( {5}^{2}  + 5x +  {x}^{2} ) =

(5 - x)(25 + 5x +  {x}^{2} )

3 0
2 years ago
Read 2 more answers
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