Question

John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

Answer 1

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

• Velocity = 30 m/s

• Angle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

$V_x = Vcos(\theta)$

Substituting the given parameters into the formula, we have;

$\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5$

Horizontal component, Vx = 15 m/s

Read more on horizontal component here: brainly.com/question/24681896