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GrogVix [38]
3 years ago
6

What is an insurance premium?*

Physics
1 answer:
aalyn [17]3 years ago
8 0

Answer:

A

Explanation:

In a nutshell, an insurance premium is the payment or installment you agree to pay a company in order to have insurance. You enter into a contract with an insurance company that guarantees payment in case of damage or loss and, for this, you agree to pay them a certain, smaller amount of money

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In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above
diamong [38]

Answer:

Va is two times greater than Vb

Explanation:

The maximum height reached by the balls are:

Ymax = \frac{Vo^2}{2g}

Since we are told that Ya = 4Yb:

Ya =  \frac{Va^2}{2g} = 4* Yb = 4 * \frac{Vb^2}{2g}

Simplifying the equation:

Va^2 = 4*Vb^2

Va = 2*Vb

5 0
3 years ago
How much work is required to move
slega [8]
<span>So we want to know how much work is needed to move a charge Q=3C for a distance r=0.01m trough a potencial difference U=9V. Work of electric potential is defined as W=Q*U and we can now simply put in the numbers. We get: W=3C*9V=27J. So the correct answer is (2) 27J. </span>
4 0
3 years ago
An Arrow (0.5 kg) travels with velocity 60 m/s to the right when it pierces an apple (1 kg) which is initially at rest. After th
Rom4ik [11]

Answer:

Velocity after collision will be 20 m/sec

Explanation:

We have given mass of arrow m_1=0.5kg

Mass of arrow v_1=60m/sec

Mass of apple m_2=1kg

Apple is at rest so velocity of apple v_2=0m/sec

According to conservation of momentum

Momentum before collision is equal to momentum after collision

m_1v_1+m_2v_2=(m_1+m_2)v

0.5\times 60+1\times 0=(0.5+1)v

1.5v=30

v = 20 m/sec

5 0
3 years ago
Please help me fast
MakcuM [25]

Answer:

b I think. sorry if it's wrong

6 0
3 years ago
PLEASE HELP ME IN THIS QUESTION!!!
kirill115 [55]

Answer:

Acceleration is 8.45 and the tension is 2.775

Explanation:

Lets apply the equation F=ma for vertical block,

5-T= 0.5a

foe the frictional force acting on the object,

f=0.11×5 (consider equation no.1)

=0.55N

Applying F=ma for the block which is on surface,

T-0.55=0.5a (consider as equation no.2)

no.1=no.2

5.55=2T

T=2.775

by equation no.1,

4.225=0.5a

a=8.45

8 0
3 years ago
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