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OverLord2011 [107]
2 years ago
13

What is the hypotenuse of a right triangle with a and b related by the statement a=b-5.

Mathematics
1 answer:
zloy xaker [14]2 years ago
8 0

Answer:

c = 5b ±sqrt(-10(b+a)+2)

Step-by-step explanation:

By using the Pythagoras theorem,

c² = a² + b²

a = b-5

b = a+5

c² = (b-5)² + (a+5)²

c² = b²-10b+25 + a²+10a+25

c² = b²-10b-10a+50

c² = b²-10(b+a)+50

c = 5b ±sqrt(-10(b+a)+2)

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This figure shows circle Z with chords AB and RS . mAR=55° mRB=66° AB=8 m RS=8 m What is mRS?
Alina [70]
M AR = 55°
m RB = 66°
Like AB=8 m =RS →m RS = m AB

m AB = m AR + m RB
m AB = 55° + 66°
m AB = 121°

m RS = m AB
M RS = 121°

Answer: m RS is 121°
4 0
4 years ago
Read 2 more answers
Please help I don’t understand
nikitadnepr [17]

Answer:

5 people

Step-by-step explanation:

For each people Ms Hernandez bring to the zoo, she will pay $15.50, so if she go alone, 1×15.50, if she go with one person, 2×15.50, with three 3×15.50, and keep growing this way. The price each person pay is constant and equal to 15.50, and what will determine the final price is the number of people. Also remember that she always will have to pay $ 10 on parking, so you can write an equation with this:

15.50x +10 = y, as x being the number of people and y being the final price.

She have $100, so this is the max she can spend. Two know the number of people she can bring to the zoo, put 100 in place of y and find the value of x:

15.50x + 10 = 100

15.50x = 100 - 10

15.50x = 90

x = 90/15.50

x = 5.8

But there's no way to bring 0.8 person, so the max she can bring are 5 people, including her

5 0
3 years ago
The diagram is not drawn to scale
Firlakuza [10]

Answer:

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6 0
3 years ago
How many times larger is 700 than 70?
Strike441 [17]
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1=10x bigger
2=100x bigger
3=1000x bigger
4=10000x bigger 
5=100000 bigger

so on and so forth. There are 2 zeros in 700, and only 1 zero in 70, the difference in zeros is 1, so you can refer to the chart and conclude that 700 is 10 times bigger than 70. You could also divide 700 by 70 to get 10. This is more accurate, but the chart is simpler.

3 0
4 years ago
Verify:<br>cos(2A)=(cotA-tanA)/cscAsecA​
kolbaska11 [484]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

cot A = \frac{cosA}{sinA}, tanA = \frac{sinA}{cosA}, cscA  = \frac{1}{sinA}, secA = \frac{1}{cosA}

Consider the right side

\frac{cotA-tanA}{cscAsecA}

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= cos²A - sin²A

= cos2A

= left side ⇒ verified

5 0
3 years ago
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